Answer: A C D
Step-by-step explanation:
Break the problem into two parts: 1) the area of the this isosceles triangle whose hypotenuse is AB and 2) the area of the semicircle whose diameter is AB.
The triangle is isosceles because the lengths of the two shorter legs are the same (2 meters). Use the Pythagorean Theorem to find the length of the hypotenuse of this triangle. (AB)^2 = (2 m)^2 + (2 m)^2, or 8 m^2. Thus, AB = sqrt(8 m^2), or 2sqrt(2). This AB is also the base of the triangle. What is the area of the triangle?
Next, noting that the diameter AB of the semicircle is 2sqrt(2) and the radius is just sqrt(2), find the area of the semicircle. The area of a circle of radius r
is pi*r^2; here it's pi*(sqrt 2)^2, or pi*2, or 2pi.
Add the area of the triangle to this area of the semicircle (2pi) to find the total area of the figure.
Hint: the area of a triangle is (bh)/2, where h is the height, b is the base.
Answer:
y - 5 = (2/3)(x + 2)
Step-by-step explanation:
Use the point-slope formula y - k = m(x - h), recognizing that h = -2, y = 5 and m = 2/3:
y - 5 = (2/3)(x + 2)
88 degrees is the answer. You would start by setting up the equation as (5x+7)+(8x+8)+(3x+5)=180 because all angles of a triangle have a sum of 180 degrees. From there you combine like terms which would leave the answer of being 16x+20=180 then you subtract the 20 from 180 to get x by itself. Then that would leave you with 16x=160 then you divide both sides by 16 to get x=10. From there you plug 16 into the x in the planetarium equation which is 8(10)+8 which equals 88 degrees
