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Mnenie [13.5K]
3 years ago
10

How many dots should be shown in the Lewis dot diagram of oxygen? (1 point)

Chemistry
1 answer:
deff fn [24]3 years ago
8 0

Answer: the answer is number 3 which is 6

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What is the attraction between molecules within a substance called? adhesion capillary action cohesion polarity.
cestrela7 [59]

Answer:

cohesion

Explanation:

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5 0
2 years ago
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iogann1982 [59]

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Explanation:

5 0
3 years ago
Consider the reaction: 2 SO2(g) + O2(g) <----> 2 SO3. If, at equilibrium at a certain temperature, [SO2] = 1.50 M, [O2] =
vlada-n [284]

Answer:

5.79

Explanation:

The following data were obtained from the question:

Concentration of SO2, [SO2] = 1.50 M

Concentration of O2, [O2] = 0.120 M

Concentration of SO3, [SO3] = 1.25 M

Equilibrium constant, (K) =..?

The balanced equation for the reaction is given below:

2SO2(g) + O2(g) <==> 2SO3(g)

From the balanced equation, the equilibrium constant K is written as follow:

K = [SO3]²/ [SO2]²• [O2]

With the above, the value of the equilibrium constant, K can be obtained as follow

K = [SO3]²/ [SO2]²• [O2]

K = (1.25)² / (1.50)² × 0.120

K = 1.5625 / ( 2.25 x 0.120)

K = 5.79

Therefore, the equilibrium constant is 5.79.

7 0
3 years ago
What are the two different ions present in the compound al(no3)3?
Aleks [24]

Al^{3+} and NO_3^{-}

Aluminum nitrate is an ionic compound, meaning that it is made up cations and anions. By convention when writing the formula for an ionic compounds the cation part shall be placed in front the anions. Thus the cation would contain aluminum and the anion shall be a polyatomic nitrate ion consisting of nitrogen and oxygen. The bracket with subscript 3 attached resembles the ratio between the two species, aluminum ions and nitrate ions. For each aluminum ion in the compound there shall be three corresponding nitrate ions.

Aluminum form ions of charge +3 whereas nitrate ions are of charge -1. Write the charge of the ion as the superscript in reverse (i.e., write 3+ as in Al^{3+} and - in NO_3^{-}, omitting any 1.)

5 0
3 years ago
A sample of gas originally at 25 C and 1.00 atm pressure in a 2.5 L container is allowed to expand until the pressure is 0.85 at
aivan3 [116]

Answer:

Final volumeof the gas = 2.84 L

Explanation:

The formular to be used here is the general gas equation. the formular is being used because it gives the relationship between the three gas parameters (volume, temperature and pressure) mentioned.

The general gas equation is given as;

\frac{P1V1}{T1} = \frac{P2V2}{T2}

where;

P1 = initial pressure

V1 = initial volume

T1 = initial temperature

P2 = Final pressure

V2 = Final volume

T2 = Final temperature

From the question,

P1 = 1.00 atm

P2 = 0.85atm

T1 = 25C + 273 = 298K (Converting to kelvin)

T2 = 15C + 273 = 288K (Converting to kelvin)

V1 = 2.5L

V2 = ?

from the equation, making V2 subject of formula we have;

V2 = \frac{T2P1V1}{T1P2}

V2 = (1*2.5*288)/(298*0.85) = 2.84 L.

5 0
3 years ago
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