Answer:
0.05 M
Explanation:
First we <u>convert 12 g of NaHSO₄ into moles</u>, using the <em>given molar mass</em>:
- 12 g NaHSO₄ ÷ 120.1 g/mol = 0.10 mol NaHSO₄
We can now <u>calculate the molarity of the resulting solution</u>, using the <em>calculated number of moles and the given volume</em>:
- Molarity = moles / liters
- Molarity = 0.10 mol / 2.00 L = 0.05 M
Answer:
Self-reduction is a reaction in which no external reducing agent is required. It is called self-reducing because copper oxide itself reduced the copper sulfide to give copper and sulfur dioxide.
Answer:
0.893mol
Explanation:
n = m ÷ M
= 275 ÷ (23 + 80)
= 2.67 mol
* now use the Mol ratio *
NaBr : FeBr3
6 : 2
2.67 : x
5.67 = 6x
n( FeBr3 ) = 0.893 mol
Water and copper hope this helps:)
<h3>
Answer:</h3>
8.01 mol MgO
<h3>
General Formulas and Concepts:</h3>
<u>Math</u>
<u>Pre-Algebra</u>
Order of Operations: BPEMDAS
- Brackets
- Parenthesis
- Exponents
- Multiplication
- Division
- Addition
- Subtraction
<u>Chemistry</u>
<u>Atomic Structure</u>
<u>Stoichiometry</u>
- Using Dimensional Analysis
- Analyzing Reactions RxN
<h3>
Explanation:</h3>
<u>Step 1: Define</u>
[RxN - Unbalanced] Mg + O₂ → MgO
[RxN - Balanced] 2Mg + O₂ → 2MgO
[Given] 8.01 moles Mg
[Solve] moles MgO
<u>Step 2: Identify Conversions</u>
[RxN] 2 mol Mg → 2 mol MgO
<u>Step 3: Stoich</u>
- [DA] Set up:

- [DA] Multiply/Divide [Cancel out units]:
