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jarptica [38.1K]
3 years ago
10

Part 1: Name the type of chemical reaction that occurs when magnesium chloride

Chemistry
1 answer:
Gala2k [10]3 years ago
3 0

Mg is ahead of Al in the electrochemical series and more reactive than Al hence Al does not react with MgCl2.

A chemical reaction is said to have occurred when new substances are formed. The reaction between magnesium chloride  solution and sodium carbonate solution is a double decomposition reaction since the cations exchange anion partners in the product;

MgCl2(aq) + Na2CO3(aq) ------> MgCO3(s) + 2NaCl(aq)

We must note that a single replacement reaction depends on the relative positions of metals in the electrochemical series. Al can react with CuCl2 because Al is more reactive than copper and ahead of Cu in the electrochemical series. On the other hand, Mg is ahead of Al in the electrochemical series and more reactive than Al hence Al does not react with MgCl2.

Lear more about electrochemical series: brainly.com/question/25749323

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A solution of citric acid (H₃C₆H₅O₇) with a known concentration of 0.200 M H₃C₆H₅O₇ is titrated with a 0.750 M NaOH solution. Ho
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The quantity of NaOH required to reach the third equivalence point is 20mL.

Using the titration formula,

CaVa/CbVb = Na/Nb

Where,

Ca = concentration of citric acid (0.200 M)

Cb = concentration of NaOH (0.750 M)

Va = Volume of citric acid (25.0 mL)

Vb = volume of NaOH (x mL)

Na = number of reacting mole of citric acid (3)

Nb = number of reacting mole of NaOH (1)

Therefore Vb ( x mL) =CaVaNb/CbNa

                                 

 = 0.2× 25×3/0.75 ×1

                                   

= 15/0.75

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How many grams of agcl would be needed to make a 4. 0 m solution with a volume of 0. 75 l?
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430 g of AgCl would be needed to make a 4.0m solution with a volume of 0.75 L.

<h3>What is Molarity?</h3>
  • The amount of a substance in a specific volume of solution is known as its molarity (M).
  • The number of moles of a solute per liter of a solution is known as molarity.
<h3>Calculation of Required amount of AgCl</h3>

Remember that mol/L is the unit of molarity (M).

We can compute the necessary number of moles of solute by multiplying the concentration by the liters of solution, according to dimensional analysis.

0.75L×4.0M=3.0mol

Then, using the periodic table's molar mass for AgCl, convert from moles to grams:

3.0mol×143.321gmol=429.963g

The final step is to round to the correct significant figure, which in this case is two: 430g.

Hence, 430 g of AgCl would be needed to make a 4.0m solution with a volume of 0.75 L.

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