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a_sh-v [17]
3 years ago
15

Find the area of the shaded region. Express your answer in terms of pi

Mathematics
1 answer:
Likurg_2 [28]3 years ago
4 0

Area of the shaded region is 540 – 65.25π.    

Solution:

Length of the rectangle = 12 + 9 + 6 + 3 = 30 in

Width of the rectangle = 18 in

Radius of the larger circle (r_1) = 12 ÷ 2 = 6 in

Radius of the medium circle (r_2) = 9 ÷ 2 = 4.5 in

Radius of the smaller circle (r_3) = 6 ÷ 2 = 3 in

Area of the shaded region = Area of the rectangle – Area of the larger circle – Area of the medium circle – Area of the smaller circle

                                   =l\times b-\pi r_1^2-\pi r_2^2-\pi r_3^2

                                   =30\times 18-\pi \times 6^2-\pi \times (4.5)^2-\pi \times 3^2

                                   =540-36\pi-20.25\pi-9\pi

                                   =540-65.25\pi

Area of the shaded region is 540 – 65.25π.    

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Four movie tickets in Germany plus 3 movie tickets in France cost &62.27 three tickets in Germany plus 4 tickets in France c
vfiekz [6]

Answer:tickets in Germany cost $8.93

tickets in France cost $8.85

Step-by-step explanation:

Let x represent the cost of a movie ticket in Germany.

Let y represent the cost of a movie ticket in France.

Four movie tickets in Germany plus 3 movie tickets in France cost &62.27. This means that

4x + 3y = 62.27 - - - - - - - - 1

three tickets in Germany plus 4 tickets in France cost $62.19

This means that

3x + 4y = 62.19 - - - - - - - - -2

Multiplying equation 1 by 3 and equation 2 by 4. It becomes

12x + 9y = 186.81

12x + 16y = 248.76

Subtracting,

- 7y = - 61.95

y = - 61.95/7

y = 8.85

Substituting y = 8.85 into equation 1, it becomes

4x + 3×8.85 = 62.27

4x + 26.55 = 62.27

4x = 62.27 - 26.55

4x = 35.72

x = 35.72/4 = 8.93

7 0
3 years ago
How did u get 4/3. Because I’m confused
Svet_ta [14]
What’s the original question and I can help!
5 0
3 years ago
Give an example for a pair of alternate interior angles, a pair of corresponding angles, and a pair of alternate exterior angles
cluponka [151]

Answer:

One way to identify alternate exterior angles is to see that they are the vertical angles of the alternate interior angles.

Step-by-step explanation:

so if I was you I would use that strategy to try to find the pair of the Alternate exterior angles.

so the agles are probably 1 and 7 but i don’t want you to get it wrong so here’s a picture Of an example.

4 0
3 years ago
One fourth of a solution that was 10 percent
Alexxx [7]
The answer is 26 because I added
6 0
3 years ago
Read 2 more answers
Find the EXACT value of sin(A−B) if cos A = 3/5 where A is in Quadrant IV and cos B = 12/13 where B is in Quadrant IV. Assume al
MissTica

\bf \textit{Sum and Difference Identities} \\\\ sin(\alpha - \beta)=sin(\alpha)cos(\beta)- cos(\alpha)sin(\beta)

well, for both angles A and B we're on the IV Quadrant, meaning, the sine is negative, the cosine is positive, likewise, the opposite side is negative and the adjacent side for the angle is positive.

\bf cos(A)=\cfrac{\stackrel{adjacent}{3}}{\underset{hypotenuse}{5}}\qquad \qquad \stackrel{\textit{getting the opposite side}}{b=\pm\sqrt{5^2-3^2}}\implies b = \pm 4 \\\\\\ \stackrel{IV~Quadrant}{b = -4}\qquad \qquad sin(A)=\cfrac{\stackrel{opposite}{-4}}{\underset{hypotenuse}{5}} \\\\[-0.35em] ~\dotfill\\\\ cos(B)=\cfrac{\stackrel{adjacent}{12}}{\underset{hypotenuse}{13}}\qquad \qquad \stackrel{\textit{getting the opposite side}}{b=\pm\sqrt{13^2-12^2}}\implies b = \pm 5

\bf \stackrel{IV~Quadrant}{b = -5}\qquad \qquad sin(B)=\cfrac{\stackrel{opposite}{-5}}{\underset{hypotenuse}{13}} \\\\[-0.35em] ~\dotfill\\\\ sin(A-B)=\cfrac{-4}{5}\cdot \cfrac{12}{13}-\left( \cfrac{3}{5}\cdot \cfrac{-5}{13} \right)\implies sin(A-B)=\cfrac{-48}{65} - \left( \cfrac{-15}{65} \right) \\\\\\ sin(A-B)=\cfrac{-48}{65} + \cfrac{15}{65}\implies sin(A-B)=\cfrac{-33}{65}

4 0
3 years ago
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