#include<stdio.h>
#include<stdlib.h>
int comment1(FILE *fp)
{
char ch;
int count=0;
while(fscanf(fp,"%c",&ch)!=EOF)
{
if(ch=='\n')
{
return count;
}
count++;
}
return count;
}
int comment2(FILE *fp)
{
char ch;
int count=0;
while(fscanf(fp,"%c",&ch)!=EOF)
{
if(ch=='*')
{
fscanf(fp,"%c",&ch);
if(ch=='/')
{
return count;
}
count++;
}
count++;
}
return 0;
}
int main()
{
printf("Enter the file name:");
char s[1000],ch,ch1;
scanf("%s",s);
FILE*fp;
fp = fopen(s,"r");
int count=0;
while(fscanf(fp,"%c",&ch)!=EOF)
{
if(ch=='\"')
{
while(fscanf(fp,"%c",&ch)!=EOF)
{
if(ch=='\"')
{
break;
}
if(ch=='\\')
{
fscanf(fp,"%c",&ch);
}
}
}
else if(ch=='/')
{
fscanf(fp,"%c",&ch);
if(ch=='/')
{
count += comment1(fp);
}
else if(ch=='*')
{
count += comment2(fp);
}
}
}
printf("%d\n",count);
return 0;
}
Answer:
1 14 3
Explanation:
If that code fragment is put under a main() function and then it will yield the above output. According to the function something(), only changes in value second parameter will be reflected and first will be unchanged because second is passed by reference and the first one is passed as value so only address of 's' is passed, so, only its value is changed and the rest are same.
Answer:
oysters
Explanation:
oysters form pearls inside their mouths, it's a very long process, and most oysters never finish or do them
please give brainliest
Cloud storage is a service model in which data is maintained, managed, backed up remotely and made available to users over a network (typically the Internet).
