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astra-53 [7]
4 years ago
5

Help me!!! I really need it

Physics
1 answer:
Alenkinab [10]4 years ago
3 0

Answer:

The reading on the ammeter A₁ , should be 2 Amp.

Explanation:

Given circuit shows all the bulbs are connected in parallel and ammeter A(T) at the source reads 6 Amp.

So, as the bulbs are in parallel connection, the current gets divided equal to each bulb.

so, the reading on the ammeter A₁ , should be 2 Amp.

But it will show 6 Amp, which is three times of the required value(2 amp).

This is because there was a mistake while making the circuit connections.

Instead of making connections as given circuit, the connections were made different as uploaded circuit.

Instead of connecting ammeter A₁ to only one bulb, it is connected to all the bulbs.

To correct this, remove the wire connecting ammeter and the second bulb.

And connect the second bulb directly to the switch.

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An object with a mass of 78 kg is lifted through a height of 6 meters how much work is done
il63 [147K]
We got the following:
m = 78kg
h = 6m
g = 9.8 m/sec^{2} ≈ 10 m/sec^{2}
----------------------------------------------------------------------------
A = ?

As we know A = Ep = mgh    ->      potential energy
so the answer would be A = 78 * 6 * 10 = 4680 Joule


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3 years ago
What happens to the kinetic energy of water when it changes from the liquid state to the solid state
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5. Confirm dimensionally that the product (lvp/n) is
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Answer:

How do you do it?

Explanation:

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The pressure at the bottom of a full barrel of water is Poriginal . Determine what happens to the pressure when the radius or he
Sholpan [36]

Answer:

a)   P' = P_original, b)  P ’= P_original + ρ  g Δh

Explanation:

The expression for nanometric pressure is

          P = ρ g h

where ρ  is the density of the liquid and h is the height

a) we change the radius of the barrel, but keeping the same height

as the pressure does not depend on the radius it remains the same

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b) We change the barrel height

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we substitute in the equation

      P ’= ρ  g h’

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      P ’= ρ  g (h + Δh)

      P ’= (ρ  g h) + ρ  g Δh

      P ’= P_original + ΔP

In this case, the pressure changes due to the new height,

*if it is higher than the initial one, the pressure increases

*if the height is less than the initial one, the pressure is less

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