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astra-53 [7]
3 years ago
5

Help me!!! I really need it

Physics
1 answer:
Alenkinab [10]3 years ago
3 0

Answer:

The reading on the ammeter A₁ , should be 2 Amp.

Explanation:

Given circuit shows all the bulbs are connected in parallel and ammeter A(T) at the source reads 6 Amp.

So, as the bulbs are in parallel connection, the current gets divided equal to each bulb.

so, the reading on the ammeter A₁ , should be 2 Amp.

But it will show 6 Amp, which is three times of the required value(2 amp).

This is because there was a mistake while making the circuit connections.

Instead of making connections as given circuit, the connections were made different as uploaded circuit.

Instead of connecting ammeter A₁ to only one bulb, it is connected to all the bulbs.

To correct this, remove the wire connecting ammeter and the second bulb.

And connect the second bulb directly to the switch.

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There’s an image here . Please help out !
ra1l [238]

Answer:

magnet 4

because opposite direction i.e north and south will attract each other

6 0
3 years ago
Read 2 more answers
A 0.400-kg object is swung in a circular path and in a vertical plane on a 0.500-m-length string. If the angular speed at the bo
Talja [164]

Answer:

T = 16.72 N

Explanation:

When the object is swung in a circular path, and in a vertical plane, there are two forces external to the object acting on it at any time: the gravity (which is always downward) and the tension in the string (which always points towards the center of the circle).

At the bottom of the circle, the tension is directly upward, so these two forces, are opposite each other, and the difference between them is the centripetal force , which at this point, keeps the object swinging in a circle.

This is the point of the trajectory where T is maximum.

We can apply Newton's 2nd Law, choosing an axis vertical (y-axis) being the upward direction the positive one, as follows:

T- m*g = m*a

The acceleration, at the bottom of the circle, is only normal (as there are no forces in the horizontal direction) , and is equal to the centripetal acceleration, as follows:

ac =  v² / r = ω²*r⇒ T- m*g = m*ω²*r

Replacing by the givens, we can solve for T as follows:

T = m* (ω²*r+g) = 0.4 kg*((8.00)² rad/sec²*0.5m)+9.8 m/s²) = 16.72 N

5 0
3 years ago
A seesaw is 4.0m long with a pivot at its midpoint. A boy who weighs 400N sits at a distance of 1.5m from the pivot. His sister
bezimeni [28]

Answer:

the girl must sit 2 cm from the pivot at the opposite end of the seesaw.

Explanation:

Given;

length of the seesaw, L = 4.0 m

weight of the boy, W₁ = 400 N

position of the boy from the pivot, d₁ = 1.5 m

weight of her sister, W₂ = 300 N

First, make a sketch of this information given;

                 0---0.5m---------------------Δ--------------------------4m

                         ↓<--------1.5m-------> <---------x--------->↓

                        400 N                                          300N

Apply the principle of moment about the pivot, to determine the value of x;

Sum of anticlockwise moment = sum of clockwise moment

400(1.5) = 300(x)

600 = 300x

x = 600/300

x = 2 cm

Thus, the girl must sit 2 cm from the pivot at the opposite end of the seesaw.

8 0
3 years ago
Krishne wants to measure the mass and volume of a key. Which tools should she use? a balance and a beaker of water a balance and
Ratling [72]
Balance and beaker of water. The balance will measure mass and the beaker will measure the volume when you take the initial volume without the key subtracting that value from the value with the key in the beaker
8 0
3 years ago
Read 2 more answers
A Porsche sports car can accelerate at 8.8 m/s^2. Determine its acceleration in km/h^2.
finlep [7]

Answer:

The acceleration expressed in the new units is 114.048 Km/h^{2}

Explanation:

To convert from m/s^{2} to Km/h^{2} it is necessary to remember that there are 1000 meters in 1 kilometer and 3600 seconds in 1 hour:

Then by means of a rule of three it is get:

8.8\frac{m}{s^{2}}.(\frac{1Km}{1000m}).(\frac{3600s}{1h})^{2}

8.8\frac{m}{s^{2}}.(\frac{1Km}{1000m}).(\frac{12960000s^{2}}{1h^{2}})

Hence, the units of meters and seconds will cancel. Notice the importance of square the ratio 3600s/1h, so that way they can match with the other units:

114.048 Km/h^2

So the acceleration expressed in the new units is 114.048 Km/h^2.

6 0
3 years ago
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