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Zinaida [17]
3 years ago
14

During which changes of state do atoms that cannot move past one another become free to move

Physics
1 answer:
Grace [21]3 years ago
4 0

Answer:

The correct answer is from solid to liquid (melting), and from liquid to gas (sublimation).

Explanation:

In the solid-state the energy of the molecules is low, so the molecules will have very little movement. In the liquid state, molecules have a higher level of energy, and as they move from solid to liquid state they acquire greater mobility. In a gaseous state, the energy level is very high and the molecules have a higher degree of mobility.

This can also be described through the predominant molecular forces in each state. The cohesion forces present in solids are stronger than those of repulsion. In the liquid state, the repulsion and attraction forces are balanced. Finally, in the gaseous state, the repulsive forces between the molecules predominate.  

Have a nice day!

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Two stationary point charges of +60.0 uC and +50.0 uC exert a repulsive force
joja [24]

Answer:

The value is r =  0.39279 \ m

Explanation:

From the question we are told that

     The first point charge is q_1 = 60.0 \mu C  =  60  *10^{-6} \ C

      The second point charge is  q_2 = 50 \mu C  =  50 *10^{-6} \  C

     The repulsive force exerted is  F  =  175 \  N

Generally the repulsive force  exerted is mathematically represented as

     F =  \frac{k * q_1 * q_2 }{r^2}

Here k is the coulomb constant with a value  k  = 9*10^{9}\ kg\cdot m^3\cdot s^{-4} \cdot A^{-2}.

So

       r =  \sqrt{\frac{ k *  q_1 * q_2 }{F} }

=>    r =  \sqrt{\frac{ 9*10^9 * 60 *10^{-6} * 50 *10^{-6}}{175} }

=>    r =  0.39279 \ m

8 0
3 years ago
After driving a portion of the route, the taptap is fully loaded with a total of 27 people including the driver, with an average
lara [203]

Answer:

compression of spring is x = 0.12 m

Assumed k = 160,000 N/m ........ Truck's suspension system

Explanation:

Given:

- The mass of average person m_p = 69 kg

- Total number of persons n_p = 27

- The mass of each goat m_g = 15 kg

- The total number of goats n_g = 3

- The mass of each chicken m_c = 3 kg

- The total number of goats n_c = 5

- The total mass of bananas m_b = 25 kg

Find:

How much are the springs compressed?

Solution:

- Using equilibrium equation on the taptap in vertical direction:

                                 F_net = F_spring - F_weight = 0

- Compute the force due to all the weights on the taptap:

                                F_weight = (n_p*m_p + n_g*m_g + n_c*m_c + m_b)*9.81

                                F_weight = (69*27 + 3*15 + 5*3 + 25)*9.81  

                                F_weight = 19109.88 N

- The restoring force of a spring is given by:

                                F_spring = k*x

Where, k is the spring stiffness and x is the displacement:

                                 F_weight = F_spring

                                 19109.88 = k*x

                                 x = 19109.88 / k

We need to assume the spring stiffness we will take k = 160,0000 N/m (trucks suspension systems). The value of the stiffness must be high enough to sustain a load of 1.911 tonnes.

                                 x = 19109.88 / 160,000

                                 x = 0.1194 m ≈ 0.12 m = 12 cm

- A compression of 12 cm seems reasonable for a taptap to carry 1.911 tonnes of load. Hence, the assumption of spring stiffness was reasonable. Hence, the compression of spring is x = 0.12 m.

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