Answer:
userpassword = {"123456",
"password",
"123456789",
"12345678",
"12345",
"111111",
"1234567",
"sunshine",
"qwerty",
"abc123"}
#We define the function that prompts the user for a password
def user_passinput():
password = input("Choose enter a password: ")
return password
#Function that checks the password
def check_password():
count = 0
check_pass = user_passinput()
if check_pass in userpassword:
print("Yay!! you entered the correct password")
elif count <10:
count = count+1
print("Please try again")
user_passinput()
else:
print ("Maximum tries exceeded")
check_password()
Explanation:
Using Python for this code, in the first line of the code, we list the dictionary of 10 most common passwords searched on the web. In line 12, we define the function that will demand the user to enter a password and return the value the user entered. Line 16 defines the function that checks if the password is common and prints to the screen either "Yay!! you entered the correct password", "Please try again" or "Maximum tries exceeded" depending on the condition that is satisfied. The last line of the code calls the check_password() function, which actually initiates the designed program.
Explain further what you mean by that.
Answer:
She should be aware several social media spectators are going to watch her content. She will get exposed on the Internet.
Explanation:
She should be aware several social media spectators are going to watch her content. She will get exposed on the Internet.
She should think before saying anything as one of his fans may complaint about her content to the police if she makes a joke about shooting up a place.
She has to be careful with his words as this may lead to termination from the job.
