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serious [3.7K]
3 years ago
14

Name all nfl players

Physics
1 answer:
Anton [14]3 years ago
6 0

Answer:

im not going to put them all but heres 50. hope it helps

 

1. Patrick Mahomes, QB, Kansas City

2. Aaron Donald, DI, Los Angeles Rams

3. Russell Wilson, QB, Seattle

4. Stephon Gilmore, CB, New England

5. Michael Thomas, WR, New Orleans

6. Lamar Jackson, QB, Baltimore

7. Quenton Nelson, OG, Indianapolis

8. Richard Sherman, CB, San Francisco

9. Christian McCaffrey, RB, Carolina

10. Drew Brees, QB, New Orleans

11. Julio Jones, WR, Atlanta

12. Ronnie Stanley, OT, Baltimore

13. Anthony Harris, S, Minnesota

14. Nick Bosa, EDGE, San Francisco

15. Dak Prescott, QB, Dallas

16. Za'Darius Smith, EDGE, Green Bay

17. Saquon Barkley, RB, New York Giants

18. Ezekiel Elliott, RB, Dallas

19. Cameron Heyward, DI, Pittsburgh

20. George Kittle, TE, San Francisco

21. Deshaun Watson, QB, Houston

22. Derrick Henry, RB, Tennessee

23. DeAndre Hopkins, WR, Arizona

24. Aaron Rodgers, QB, Green Bay

25. Justin Simmons, S, Denver

26. Mitchell Schwartz, OT, Kansas City

27. Danielle Hunter, EDGE, Minnesota

28. Tom Brady, QB, Tampa Bay

29. Mike Evans, WR, Tampa Bay

30. Zack Martin, OG, Dallas

31. Travis Kelce, TE, Kansas City

32. Kenny Clark, DI, Green Bay

33. DeForest Buckner, DI, Indianapolis

34. Devin McCourty, S, New England

35. Bobby Wagner, LB, Seattle

36. Tyrann Mathieu, S, Kansas City

37. Shaquil Barrett, EDGE, Tampa Bay

38. Davante Adams, WR Green Bay

39. Taylor Lewan, OT, Tennessee

40. Tre'Davious White, CB, Buffalo

41. Earl Thomas III, S, Baltimore

42. Chris Jones, DI, Kansas City

43. Eric Kendricks, LB, Minnesota

44. Darius Leonard, LB, Indianapolis

45. Rodney Hudson, C, Las Vegas

46. Fletcher Cox, DI, Philadelphia

47. Chandler Jones, EDGE, Arizona

48. Brandon Brooks, OG, Philadelphia

49. Lane Johnson, OT, Philadelphia

50. Cameron Jordan, EDGE, New Orleans

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Answer:

R=25Ω

Explanation:

Given data:

R1=3 Ω

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Now,

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R=R1+R2+R3

put the values,

R=3+8+14

R=25Ω

6 0
3 years ago
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Coal is lifted out of a mine a vertical distance of 50 m by an engine that supplies 500 W to a conveyer belt. How much coal per
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mass = 61.16 kg

Explanation:

given data

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to find out

mass

solution

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that is

energy = m×g×h    .............1

put here all value m mass here and g = 9.81 and h is distance

energy = m×g×h

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