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3 years ago

Name all nfl players

Physics

1 answer:

Anton [14]3 years ago

6 0

Answer:

im not going to put them all but heres 50. hope it helps

1. Patrick Mahomes, QB, Kansas City

2. Aaron Donald, DI, Los Angeles Rams

3. Russell Wilson, QB, Seattle

4. Stephon Gilmore, CB, New England

5. Michael Thomas, WR, New Orleans

6. Lamar Jackson, QB, Baltimore

7. Quenton Nelson, OG, Indianapolis

8. Richard Sherman, CB, San Francisco

9. Christian McCaffrey, RB, Carolina

10. Drew Brees, QB, New Orleans

11. Julio Jones, WR, Atlanta

12. Ronnie Stanley, OT, Baltimore

13. Anthony Harris, S, Minnesota

14. Nick Bosa, EDGE, San Francisco

15. Dak Prescott, QB, Dallas

16. Za'Darius Smith, EDGE, Green Bay

17. Saquon Barkley, RB, New York Giants

18. Ezekiel Elliott, RB, Dallas

19. Cameron Heyward, DI, Pittsburgh

20. George Kittle, TE, San Francisco

21. Deshaun Watson, QB, Houston

22. Derrick Henry, RB, Tennessee

23. DeAndre Hopkins, WR, Arizona

24. Aaron Rodgers, QB, Green Bay

25. Justin Simmons, S, Denver

26. Mitchell Schwartz, OT, Kansas City

27. Danielle Hunter, EDGE, Minnesota

28. Tom Brady, QB, Tampa Bay

29. Mike Evans, WR, Tampa Bay

30. Zack Martin, OG, Dallas

31. Travis Kelce, TE, Kansas City

32. Kenny Clark, DI, Green Bay

33. DeForest Buckner, DI, Indianapolis

34. Devin McCourty, S, New England

35. Bobby Wagner, LB, Seattle

36. Tyrann Mathieu, S, Kansas City

37. Shaquil Barrett, EDGE, Tampa Bay

38. Davante Adams, WR Green Bay

39. Taylor Lewan, OT, Tennessee

40. Tre'Davious White, CB, Buffalo

41. Earl Thomas III, S, Baltimore

42. Chris Jones, DI, Kansas City

43. Eric Kendricks, LB, Minnesota

44. Darius Leonard, LB, Indianapolis

45. Rodney Hudson, C, Las Vegas

46. Fletcher Cox, DI, Philadelphia

47. Chandler Jones, EDGE, Arizona

48. Brandon Brooks, OG, Philadelphia

49. Lane Johnson, OT, Philadelphia

50. Cameron Jordan, EDGE, New Orleans

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bearhunter [10]

Answer:

Weight in Air = 0.3N

Weight in Water = 0.25N

Weight in Liquid = 0.24N.

Upthrust /Buoyant Force = Weight in Air – Weight in Fluid(Water in this case)

= 0.3 – 0.25

= 0.5N.

b) R.D of Body = Density of Body/Density of Standard Fluid(Water).

There's a Derived Formula for RD.

I'm gonna Apply it here.

Ask me for the derivation in the Comment section if you need it.

RD = α/ρ = (Weight in Air) / (Upthrust Force)

Where

α = density of the Body(or reference substance)

ρ = density of standard fluid (water)

= 0.3/0.05 = 6.

c) RD of Liquid = (Density of Liquid) /(Density of standard Fluid(water)

Or we just go by that formula

RD of Liquid = Weight in Air/Upthrust(In Liquid)

We'll be using the Upthrust in that Liquid now.

= 0.3 – 0.24 = 0.06

RD = 0.3/0.06 = 5.

7 0

3 years ago

An object possesses both potential (PE) and kinetic (KE) energy. The object’s total mechanical energy is

Nina [5.8K]

Answer: PE+KE

Explanation:

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3 years ago

Read 2 more answers

What is the potential energy at the origin due to an electric field of 5 x 10^6 N/C located at x=43cm,y=28cm?

Fudgin [204]

Answer:

potential energy at origin is $2.57*10^{6} volt$

Explanation:

given data:

electric field E = 5*10^{6} N/C

at x = 43 cm, y = 28 cm

distance btween E and origin

$\Delta r = \sqrt{43^2 +28^2}$

$\Delta r = 51.313 cm$

potential energy per unit charge $\Delta V = - Edr$

$\Delta V = 5*10^6*51.313*10^{-2} J/C$

$\Delta V = 2.57*10^{6} volt$

potential energy at origin is 2.57*10^{6} volt

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4 years ago

Which of the following statements are true about the lenses used in eyeglasses to correct nearsightedness and farsightedness? (T

Slav-nsk [51]

Answer:

A: They produce a real image.

Explanation:

The images formed on the retina of the eye for a normal visibility must always be real.

Only a real image can be physically projected on any physical object whereas the virtual images are visible due to reflections.

The nearsightedness is corrected with the help of a concave lens since it is the condition of the eye lens remaining thick and curved to converge the rays entering the eyes after a shorter distance which results in their image formation even before the retinal surface so to initially diverge them a bit so that they converge on the retinal surface and form the image there we use concave lens. Vice-versa of the above justification in the case of farsightedness.

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3 years ago

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Rufina [12.5K]

Answer:

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3 years ago