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Misha Larkins [42]

3 years ago

15

A zinc atom loses 3electron to become a zinc oin

1 answer:

Alik [6]3 years ago

6 0

It lost 3 electron, meaning IT will become an ion. Also, since it specifically LOST, it would be a cation, and gain a positive charge.

Answer: True

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A brick mason builds a simple machine to lift bricks from the ground up to the second story of a building. The machine requires

Iteru [2.4K]

Answer: A MA = 0.048

Explanation: 35 divided by 735 is equal to 0.048

4 0

3 years ago

as an aid in understanding this problem. The drawing shows a positively charged particle entering a 0.61-T magnetic field. The p

miv72 [106K]

Answer:

E = 420.9 N/C

Explanation:

According to the given condition:

$Net\ Force = 2(Magnetic\ Force)\\Electric\ Force - Magnetic\ Force = 2(Magnetic\ Force)\\Electric\ Force = 3(Magnetic\ Force)\\qE = 3qvBSin\theta\\E = 3vBSin\theta$

where,

E = Magnitude of Electric Field = ?

v = speed of charge = 230 m/s

B = Magnitude of Magnetic Field = 0.61 T

θ = Angle between speed and magnetic field = 90°

Therefore,

$E = (3)(230\ m/s)(0.61\ T)Sin90^o$

<u>E = 420.9 N/C</u>

3 0

3 years ago

Calculate the speed of a car that travels 250 miles in 4.0 hours. (remember your unit)

MrRa [10]

250/4= 62.5 mph

to find the mph of a car, you need to divide the number of miles traveled by the hours that it took to travel that many miles

6 0

3 years ago

Human centrifuges are used to train military pilots and astronauts in preparation for high-g maneuvers. A trained, fit person we

jeka57 [31]

(a) $4.14 rad/s^2$

The relationship beween centripetal acceleration and angular speed is

$a=\omega^2 r$

where

$\omega$ is the angular speed

r is the radius of the circular path

Here we gave

$a = 9g = 88.2 m/s^2$ is the centripetal acceleration

r = 5.15 m is the radius

Solving for $\omega$ , we find:

$\omega = \sqrt{\frac{a}{r}}=\sqrt{\frac{88.2 m/s^2}{5.15 m}}=4.14 rad/s^2$

(b) 21.3 m/s

The relationship between the linear speed and the angular speed is

$v=\omega r$

where

v is the linear speed

$\omega$ is the angular speed

r is the radius of the circular path

In this problem we have

$\omega=4.14 rad/s$

r = 5.15 m

Solving the equation for v, we find

$v=(4.14 rad/s)(5.15 m)=21.3 m/s$

7 0

3 years ago

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Which object has the least amount of kinetic energy? a car driving down a road a soccer ball rolling down a hill a bicycle locke

mars1129 [50]

<span> a bicycle locked to a bike rack im pretty sure</span>

7 0

3 years ago

Read 2 more answers