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Misha Larkins [42]

3 years ago

15

A zinc atom loses 3electron to become a zinc oin

1 answer:

Alik [6]3 years ago

6 0

It lost 3 electron, meaning IT will become an ion. Also, since it specifically LOST, it would be a cation, and gain a positive charge.

Answer: True

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As you run , your feet push on the ground with a force 500N . The ground pushes back on your feet with a force of 500N . (Please

Mademuasel [1]

Answer:

true

Explanation:

newtons third law says to every action there is always an equal and opposite reaction. so the answer is true

3 0

3 years ago

Read 2 more answers

If a set of scores has a mean of 100.00 and

AnnyKZ [126]

Answer:

Variance is 25

Explanation:

Recall that the standard deviation is defined as the square root of the variance. therefore, if you know the standard deviation $(\sigma)$ , square it and you get the variance:

$Variance= \sigma^2\\Variance= 5^2= 25$

5 0

3 years ago

Two spherical asteroids have the same radius R. Asteroid 1 has mass M and asteroid 2 has mass 1.97·M. The two asteroids are rele

nekit [7.7K]

Answer:

$0.536\sqrt{\frac{GM}{R}}$

Explanation:

We are given that

Mass of one asteroid 1, $m_1=M$

Mass of asteroid 2, $m_2=1.97 M$

Initial distance between their centers,d=13.63 R

Radius of each asteroid=R

d'=R+R=2R

Initial velocity of both asteroids

$u=0$

We have to find the speed of second asteroid just before they collide.

According to law of conservation of momentum

$(m_1+m_2)u=m_1v_1+m_2v_2$

$(M+1.97 M)\times 0=Mv_1+1.97Mv_2$

$Mv_1=-1.97 Mv_2$

$v_1=-1.97v_2$

According to law of conservation of energy

$Gm_1m_2(\frac{1}{d'}-\frac{1}{d})=\frac{1}{2}m_1v^2_1+\frac{1}{2}m_2v^2_2$

$GM(1.97M)(\frac{1}{2R}-\frac{1}{13.63R})=\frac{1}{2}M(-1.97v_2)^2+\frac{1}{2}(1.97M)v^2_2$

$1.97M^2G(\frac{13.63-2}{27.26R})=\frac{1}{2}Mv^2_2(3.8809+1.97)$

$1.97MG(\frac{11.63}{27.26 R})=\frac{1}{2}(5.8509)v^2_2$

$v^2_2=\frac{1.97GM\times11.63\times 2}{27.26R\times 5.8509}$

$v_2=\sqrt{\frac{1.97GM\times11.63\times 2}{27.26R\times 5.8509}}$

$v_2=0.536\sqrt{\frac{GM}{R}}$

Hence, the speed of second asteroid = $0.536\sqrt{\frac{GM}{R}}$

8 0

3 years ago

What is the acceleration of a car that goes from 0 MS to 60 MS and six seconds

Len [333]

A = Δv/Δt
a = v2-v1/t2-t1
a = 60MS - 0MS / 6 seconds
a = 60 MS/ 6 seconds
a = 10 m/s^2

8 0

3 years ago

Calculate 9 ∙ 10-5 divided by 3 ∙ 10-9. (Box after the "10" in answer is for the exponent.).

Papessa [141]

Answer:

3 × 10⁴

Explanation:

We are given two numbers, $n_1=9\times 10^{-5}$ and $n_2=3\times 10^{-9}$

We have to divide n₁ by n₂. We know that,

$\dfrac{10^n}{10^m}=10^{n-m}$

Here, n = -5 and m = -9

So on dividing we get :

$\dfrac{9\times 10^{-5}}{3\times 10^{-9}}=3\times 10^{-5+9}=3\times 10^4$

Hence, on dividing n₁ by n₂ obtained number is 3 × 10⁴.

6 0

3 years ago