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zlopas [31]
3 years ago
8

A current is established in a gas discharge tube when a sufficiently high potential difference is applied across the two electro

des in the tube. The gas ionizes; electrons move toward the positive terminal and singly charged positive ions move toward the negative terminal. What is the current in a hydrogen discharge tube in which 3.4 ✕ 1018 electrons and 1.4 ✕ 1018 protons move past a cross-sectional area of the tube each second? (Enter the magnitude.)
Physics
1 answer:
pishuonlain [190]3 years ago
8 0

Explanation:

It is given that the number of electrons passing through the cross-sectional area in 1 s is 3.4 \times 10^{18}. Also, we know that charge on an electron is -1.60 \times 10^{-19} C, then negative charge crossing to the left per second is  as follows.

         I- = 3.4 \times 10^{18} electrons \times -1.6 x 10^{-19} C/electrons

         I- = 0.544 A

As it is given that the number of protons crossing per second is 1.4 \times 10^{18}, as the charge on the proton is +1.60 \times 10^{-19} C, then positive charge crossing to the right per second is calculated as follows.

          I+ = 1.4 \times 10^{18} electrons \times 1.6 \times 10^{-19} electrons/C

            I+ = 0.224 A

          I = l I+ l + l I- l

So,    I = 0.544 + 0.224

            = 0.768 A

Thus, we can conclude that the current in given hydrogen discharge tube is 0.768 A.

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What pressure will 14. 0 g of co exert in a 3. 5 l container at 75°c?
Ronch [10]

The pressure will 14. 0 g of co exert in a 3. 5 l container at 75°c is 4.1atm.

Therefore, option A is correct option.

Given,

Mass m = 14g

Volume= 3.5L

Temperature T= 75+273 = 348 K

Molar mass of CO = 28g/mol

Universal gas constant R= 0.082057L

Number of moles in 14 g of CO is

n= mass/ molar mass

= 14/28

= 0.5 mol

As we know that

PV= nRT

P × 3.5 = 0.5 × 0.082057 × 348

P × 3.5 = 14.277

P = 14.277/3.5

P = 4.0794 atm

P = 4.1 atm.

Thus we concluded that the pressure will 14. 0 g of co exert in a 3. 5 l container at 75°c is 4.1atm.

learn more about pressure:

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5 0
1 year ago
Which letter represents the position of maximum potential energy of the pendulum
worty [1.4K]
If you mean the SI Unit of GPE, the answer is J for Joules.
if that's not the question being asked, i would need a little more elaboration please :)
4 0
3 years ago
Visible light falls into wavelength ranges of 400-700 nm, for which 1 m = 1 × 10 9 nm . The energy and wavelength of light are r
Paul [167]

Answer:

E = 3.54 x 10⁻¹⁹ J

Explanation:

The energy of the photon can be given in terms of its wavelength by the use of the following formula:

E = \frac{hc}{\lambda}

where,

E = energy = ?

h = Plank's Constant = 6.626 x 10⁻³⁴ Js

c = speed of light = 2.998 x 10⁸ m/s

λ =  wavelength of light = 560.6 nm = 5.606 x 10⁻⁷ m

Therefore,

E = \frac{(6.626\ x\ 10^{-34}\ Js)(3\ x\ 10^8\ m/s)}{5.606\ x\ 10^{-7}\ m}\\

<u>E = 3.54 x 10⁻¹⁹ J</u>

7 0
3 years ago
(a) when rebuilding her car's engine, a physics major must exert 300 n of force to insert a dry steel piston into a steel cylind
Vilka [71]
There are some missing data in the text of the problem. I've found them online:
a) coefficient of friction dry steel piston - steel cilinder: 0.3
b) coefficient of friction with oil in between the surfaces: 0.03

Solution:
a) The force F applied by the person (300 N) must be at least equal to the frictional force, given by:
F_f = \mu N
where \mu is the coefficient of friction, while N is the normal force. So we have:
F=\mu N
since we know that F=300 N and \mu=0.3, we can find N, the magnitude of the normal force:
N= \frac{F}{\mu}= \frac{300 N}{0.3}=1000 N

b) The problem is identical to that of the first part; however, this time the coefficienct of friction is \mu=0.03 due to the presence of the oil. Therefore, we have:
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3 years ago
What type of energy is sunlight referred as?
nordsb [41]
The sun's energy is refferd to solor energy
5 0
4 years ago
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