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andreyandreev [35.5K]
3 years ago
5

Describe two rights and two responsibilities that you have as an employee

Physics
2 answers:
Lubov Fominskaja [6]3 years ago
7 0

Answer:

Explanation:

According to me as an employee two rights include:

  1. Right to have safe occupational condition.
  2. Right to get appropriate money for your work.

Two responsibilities include:

  1. Responsibility to do your work honestly.
  2. Responsibility to respecting your co-workers and maintaining decorum.

For example, worker working in a industry have the right to get appropriate amount of holidays to refresh themselves.

Pachacha [2.7K]3 years ago
5 0
As an employee you have the right to receive money but the responsability to work as your advisor ask you for
as an employee you have the right to work safety but the responsability to do all is accept ,and respectul by that way you can save your life and other by the same time

i can give you a last exemple

as an employee you have the right to have holyday break because you also need to be with your family but the responsability to stay in work when you have to
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Which property do gas particles at the same temperature share?
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When did agriculture first began?​
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4 0
3 years ago
A crate lies on a plane tilted at an angle θ = 22.5 ∘ to the horizontal, with μk = 0.19.
ValentinkaMS [17]

A) 2.03 m/s^2

Let's start by writing the equation of the forces along the directions parallel and perpendicular to the incline:

Parallel:

mg sin \theta - \mu_k R = ma (1)

where

m is the mass

g = 9.8 m/s^2 the acceleration of gravity

\theta=22.5^{\circ}

\mu_k = 0.19 is the coefficient of friction

R is the normal reaction

a is the acceleration

Perpendicular:

R-mg cos \theta =0 (2)

From (2) we find

R=mg cos \theta

And substituting into (1)

mg sin \theta - \mu_k mg cos \theta = ma

Solving for a,

a=g sin \theta - \mu_k g cos \theta = (9.8)(sin 22.5)-(0.19)(9.8)(cos 22.5)=2.03 m/s^2

B) 5.94 m/s

We can solve this part by using the suvat equation

v^2-u^2=2as

where

v is the final velocity

u is the initial velocity

a is the acceleration

s is the displacement

Here we have

v = ?

u = 0 (it starts from rest)

a=2.03 m/s^2

s = 8.70 m

Solving for v,

v=\sqrt{u^2+2as}=\sqrt{0+2(2.03)(8.70)}=5.94 m/s

6 0
3 years ago
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