Answer:
a).
b).rpm
c).v=0.5865 m/sec.
Explanation:
Given:
a).
The angular speed in radians per seconds is
b).
rpm
c)
Child's distance per revolution
(pi*2r) = 43.988 metres.
v=(43.988 x 0.0133333) = 0.5865 m/sec.
Answer:
Density is an important physical property of matter. It reflects how closely packed the particles of matter are. When particles are packed together more tightly, matter has greater density.
Explanation:
Momentum of the bullet is m×v = 0.01 kg × 800 m/s = 8 kgm/s
so momentum of baseball also= 8 kgm/s
8= mass of baseball × velocity
8= 0.145 × v
on solving for v,
v= 55.17 m/s which is the required velocity
: )
Answer:
elastic partial width is 2.49 eV
Explanation:
given data
ER E = 250 eV
spin J = 0
cross-section magnitude σ = 1300 barns
peak P = 20ev
to find out
elastic partial width W
solution
we know here that
σ = λ²× W / ( E × π × P ) ...................1
put here all value
σ = (0.286)² × W × / ( 250 × π × 20 )
1300 × = (0.286)² × W × / ( 250 × π × 20 )
solve it and we get W
W = 249.56 ×
so elastic partial width is 2.49 eV