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OlgaM077 [116]
3 years ago
13

A 15kg projectile is moving with a velocity of 25m/s calculate its momentum

Physics
1 answer:
aliina [53]3 years ago
8 0

The momentum of an object is given by:

p = mv

m is the object's mass and v is its velocity.

Given values:

m = 15kg

v = 25m/s

Plug in the values and solve for p:

p = 15*25

p = 375kg×m/s

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If a rock climber accidentally drops a 52.5-g piton from a height of 325 meters, what would its speed be just before striking th
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Ignoring air resistance, the Kinetic energy before hitting the ground will be equal to the potential energy of the Piton at the top of the rock.  
So we have 1/2 MV^2 = MGH 
V^2 = 2GH 
V = âš2GH 
V = âš( 2 * 9.8 * 325)  
V = âš 6370
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6 0
3 years ago
The rock starts as a solid and then..
alina1380 [7]

Answer:

they stay a solid

Explanation:

breaks apart do to whether such as erosion

7 0
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Which energy source is one that is used to boil water to make steam in power stations
Blizzard [7]

Answer:

heat energy is used in boiling water and to make steam at power stations

Explanation:

4 0
2 years ago
Which law of physics relates electric fields and current
riadik2000 [5.3K]

Answer:

Ohms law

Explanation:

Which states that the current flowing through any cross-section of the conductor is directly proportional to the potential differenceapplied across its end, provided physical conditions like temperature and pressure remain constant.

7 0
3 years ago
What current flows through a 2.56-cm-diameter rod of pure silicon that is 20.0 cm long, when 1.00 ✕ 103 V is applied to it? (Suc
vfiekz [6]

Answer:

Current, I = 0.0011 A

Explanation:

It is given that,

Diameter of rod, d = 2.56 cm

Radius of rod, r = 1.28 cm = 0.0128 m

The resistivity of the pure silicon, \rho=2300\ \Omega-m

Length of rod, l = 20 cm = 0.2 m

Voltage, V=1\times 10^3\ V

The resistivity of the rod is given by :

R=\rho\dfrac{L}{A}

R=2300\ \Omega-m\dfrac{0.2\ m}{\pi (0.0128\ m)^2}

R = 893692.30 ohms

Current flowing in the rod is calculated using Ohm's law as :

V = I R

I=\dfrac{V}{R}

I=\dfrac{10^3\ V}{893692.30\ \Omega}

I = 0.0011 A

So, the current flowing in the rod is 0.0011 A. Hence, this is the required solution.

6 0
3 years ago
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