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algol [13]
3 years ago
14

Write an equation of the line that passes through (−5, −2)(−5, −2) and is parallel to y=23x+1y=23x+1.

Mathematics
1 answer:
Klio2033 [76]3 years ago
7 0
Assuming you meant 2/3
y=2/3x+1 and (-5,-2)

paralell means same slope
y=mx+b
m=slope

y=2/3x+1
sllope=2/3

point slope
y-y1=m(x-x1)
for slope=m
a point is (x1,y1)

slope=2/3
point=(-5,-2)

y-(-2)=2/3(x-(-5))
y+2=2/3(x+5)
or
y=2/3x+16/3

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Answer:

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Step-by-step explanation:

So we have the equation:

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First, let's subtract 16 from both sides:

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Now, let's divide both sides by 3:

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Remember that with fractional exponents, we can move the denominator into the root position. Therefore:

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Let's take the fourth root of both sides. Since we're taking an even root, make sure to have the plus-minus symbol!

\sqrt[3]{x-4} =\pm 2

Cube both sides. Since we're cubing, the plus-minus stays.

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Calculator:

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So, our answer is A.

And we're done!

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