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ELEN [110]
3 years ago
10

What number could be a common denominator for these two fractions?

Mathematics
1 answer:
Aloiza [94]3 years ago
8 0

Answer:

it is 12

Step-by-step explanation:

You might be interested in
In a five-card poker hand, what is the probability of being dealt exactly one nine and no picture cards?
earnstyle [38]

Answer:

0.0907

Step-by-step explanation:

There are 12 picture cards

There are 4 9's

There are 52-12-4 = 36 cards that are not 9's and not picture cards

(5*58905)/(52C5)

3 0
3 years ago
Find an obtuse angle whose sine is<br> a) 0.25<br> b) 0.75<br> c) 0.875<br> d) 0.3465
swat32

Answer:

a) 165.52 degrees.

b)  131.41 degrees.

c)  118.96 degrees.

d)  159.73 degrees.

Step-by-step explanation:

The sine of an obtuse angle is positive as it is in the second quadrant.

a) Using a calculate the angle whose sine ( arcsin) is 0.25  = 14.478 degrees

so the obtuse angle  = 180 - 14.478 = 165.52 degrees to nearest hundredth

b) c) and d) are calculated in the same way.

7 0
3 years ago
CAN U GUYS HELP? WE REVIEWED THIS IN 8TH GRADE IM NOW A FRESHMAN AND COMPLETELY FORGOT! PLEASE HELP ASAP!
uranmaximum [27]
B because -4-6 = -10, so -4+-6 also equals -10
7 0
4 years ago
Read 2 more answers
I'm blanking on how to do this, I learned it so long ago, any help would be greatly appreciated. More interested on how to do it
anyanavicka [17]

Answer:

\dfrac{16 y^{22}}{x^{10}z^{10}}

Step-by-step explanation:

Given expression is ,

\sf\longrightarrow \bigg(\dfrac{2x^3y^{-5}z^8}{8x^{-2}y^6z^3}\bigg)^{-2}

This would be simplified using the law of exponents , some of which I will use here are ,

  • (an)^m = a^m n^m
  • \dfrac{a^m}{a^n}=a^{m-n}

  • a^m a^n = a^{m+n}
  • a^{-n} = \dfrac{1}{a^n}

Using the above laws ,

\sf \longrightarrow \bigg[ \dfrac{2}{8} \bigg(\dfrac{x^3}{x^{-2}}\bigg)\bigg(\dfrac{y^{-5}}{y^6}\bigg)\bigg(\dfrac{z^8}{z^3}\bigg)  \bigg]^{-2}

Using the second law mentioned above , we have,

\sf \longrightarrow \bigg[ \dfrac{1}{4}(x^{3+2})(y^{-5-6})(z^{8-3})\bigg]^{-2}

Simplify ,

\sf \longrightarrow \bigg[\dfrac{1}{4} x^5y^{-11}z^5\bigg]^{-2}

Using the first law mentioned above , we have,

\sf \longrightarrow \bigg[ \dfrac{1}{4^{-2}} x^{5(-2)} y^{-11(-2)} z^{5(-2)}\bigg]

Simplify,

\sf \longrightarrow 4^2x^{-10}y^{22} z^{-10}

Finally using the fourth law mentioned above , we have ,

\sf \longrightarrow \boxed{\bf \dfrac{16 y^{22}}{x^{10}z^{10}}}

<h3>Option K is the correct answer.</h3>
4 0
2 years ago
What does the line 2x+5y=5 look like
JulsSmile [24]
This is what it would look like

8 0
4 years ago
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