What number could be a common denominator for these two fractions?

Probability of landing in the white not the red. Please helpppppppppppp!

Iteru [2.4K]

Fun, geometry disguised as probability.

That's a pentagon, which we can view as 10 right triangles with legs a and s/2 (half of s) and hypotenuse r. So area of the pentagon is

P = 10 × (1/2) a (s/2) = 10 (1/2) (3.2) (4.7/2) = 37.6

The area of the circle is πr² so the circle area is

C = π (4²) = 50.265482

The white area is the difference, C-P, and the probability we seek is the fraction of the circle that's white, so (C-P)/C.

p = (C-P)/C =1-P/C = 1-37.6/50.265482 = 0.251971

Answer: 0.25

Higher than I would have guessed from the figure.

7 0

3 years ago

An education researcher claims that 58% of college students work year-round. In a random sample of 400 college students, 232

Hatshy [7]

Answer:

The proportion of college students who work year-round is 58%.

Step-by-step explanation:

The claim made by the education researcher is that 58% of college students work year-round.

A random sample of 400 college students, 232 say they work year-round.

To test the researcher's claim use a one-proportion z-test.

The hypothesis can be defined as follows:

H₀: The proportion of college students who work year-round is 58%, i.e. p = 0.58.

Hₐ: The proportion of college students who work year-round is 58%, i.e. p ≠ 0.58. C

Compute the sample proportion as follows:

$\hat p=\frac{232}{400}=0.58$

Compute the test statistic value as follows:

$z=\frac{\hat p-p}{\sqrt{\frac{p(1-p)}{n}}}=\frac{0.58-0.58}{\sqrt{\frac{0.58(1-0.58)}{400}}}=0$

The test statistic value is 0.

Decision rule:

If the p-value of the test is less than the significance level then the null hypothesis will be rejected.

Compute the p-value for the two-tailed test as follows:

$p-value=2\times P(z$

*Use a z-table for the probability.

The p-value of the test is 1.

The p-value of the test is very large when compared to the significance level.

The null hypothesis will not be rejected.

Thus, it can be concluded that the proportion of college students who work year-round is 58%.

6 0

3 years ago

13 ? start fraction, 13, divided by, 10, end fraction of a number is what percentage of that number?

zubka84 [21]

Answer:

The percentage is $130\%$

Step-by-step explanation:

Let

x-----> the number

we have

$\frac{13}{10}x=1.3x$

To find the percentage multiply by 100

$1.3*100=130\%$

7 0

2 years ago

Please help I don’t understand it’s like angles and stuff picture above. 20 POINTS WILK MARK BRAINLEST FOR RIGHT ANSWERS ONLY

oksano4ka [1.4K]

Since 6x - 44 and 88 degrees are the same (exterior angles), we can start off with the first equation, 6x - 44 = 88

6x - 44 = 88

+44 +44

6x = 132

÷6 ÷6

x = 22

same with the second problem (exterior angles are equal):

equation:

15x + 6 = 9x + 54

-6 -6

15x = 9x + 48

-9x -9x

6x = 48

÷6 ÷6

x = 8

Hope this helped! :D

5 0

2 years ago

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FiftyFifty adult men in the United States are randomly selected and measured for their body mass index (BMI). Based on that sa

Fynjy0 [20]

Answer: $(23.3,\ 29.7)$

Step-by-step explanation:

The confidence interval for population mean is given by :-

$\overline{x}\pm ME.$ , where $\overline{x}$ is the sample mean and ME is the margin of error .

Given : The sample mean : $\overline{x}=26.5$

Margin of error : $ME=3.2$

Then , the range of values (confidence interval) likely to contain the true value of the population parameter will be :-

$26.5\pm 3.2=(26.5-3.2,\ 26.5+3.2)=(23.3,\ 29.7)$

Hence, the range of values likely to contain the true value of the population parameter = $(23.3,\ 29.7)$

3 0

3 years ago

Read 2 more answers