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Assoli18 [71]
3 years ago
15

Where do the lemons go after harvested? What gets done with lemons?

Chemistry
1 answer:
Temka [501]3 years ago
5 0

Answer:

Lemon juice,lemonade

Explanation:

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Which of the following transitions represent the emission of a photon with the largest energy?
s2008m [1.1K]

Answer:

n=6 to n=3 (B)

Explanation:

Energy of an electron present in the n^{th} orbit is directly proportional to n^{2} .Hence a transistion from one orbit to another orbit emits an energy proportional to the difference of their squares of the orbits. that is if an electron travels from orbit n1 to orbit n2 then it emits an energy corresponding to n_{1} ^{2} -n_{2} ^{2}.So in the above question the highest energy emission occurs when an electron moves from n=6 to n=3.(Highest difference of energy levels).

6 0
3 years ago
Find the equation of directrix of the parabola is given by 64x equals to -ySquare ​
ANEK [815]

Answer:

Given equation of parabola is

and

2

=64x ......(i)

The point at which the tangent to the curve is parallel to the line is the nearest point on the curve.

On differentiating both sides of equation (i), we get

2 y

dx

d y

=64

⇒

dx

d y

=

and

32

Also, slope of the given line is −

3

4

∴−

3

4

=

and

32

⇒and=−24

From equation (i), (−24)

2

=64x⇒x=9

∴ the required point is (9,−24)

Explanation:

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5 0
3 years ago
How can you demonstrate waves?​
Lady bird [3.3K]
Shaking a phone cord, strumming a guitar string, playing a trumpet
7 0
3 years ago
A substance freezes at -58 celcius. Therefore a substance melts at: ________________
Liono4ka [1.6K]
-58 °C
The melting point is the same as the freezing point.
4 0
3 years ago
0.350 mol of a solid was dissolved in 260 mL of water at 21.2 oC. After the solid had fully dissolved, the final temperature of
Fittoniya [83]

Answer: Heat of the solution  = mass water × specific heat water × change in temperature

mass water = 260ml (1.00g/ml ) = 260g

specific heat of water = c(water) = 4.184J/ g°C

Heat change of water = final temperature - initial temperature

                                       = 26.5 - 21.2

                                        = 5.3 °C

H = 260 g ( 4.184J/g°C ) (5.3°C) = 5765J

Molar heat = \frac{5765J}{0.350mol}

                    = 16473J/mol

Explanation: finding molar heat requires first to look at  specific heat of water and the change of water temperature

7 0
3 years ago
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