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Drupady [299]
2 years ago
6

14. Convert 4084 grams of NH3 kept at -40°C to Liters at STP. The density as a liquid is

Chemistry
1 answer:
Zigmanuir [339]2 years ago
5 0

The density of the gas can be given by the mass of the substance and its volume. A 4084 gms of ammonia has a volume of 5.99 L.

<h3>What is STP?</h3>

STP is the condition at which the temperature and the pressure of the gas are at the normal and standard conditions.

The density of the ammonia = 681.9gm/L

The mass = 4084 gm

The volume is calculated as:

V = Mass ÷ Volume

= 4084 ÷ 681.9

= 5.99 L

Therefore, at STP the volume of ammonia is 5.99 L.

Learn more about STP here:

brainly.com/question/19678676

#SPJ1

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The answer is B hope it helped

3 0
3 years ago
What is the standard electrode potential for a galvanic cell constructed in the appropriate way from these two half-cells?
____ [38]

E

θ

Cell

=

+

2.115

l

V

Cathode

Mg

2

+

/

Mg

Anode

Ni

2

+

/

Ni

Explanation:

Look up the reduction potential for each cell in question on a table of standard electrode potential like this one from Chemistry LibreTexts. [1]

Mg

2

+

(

a

q

)

+

2

l

e

−

→

Mg

(

s

)

−

E

θ

=

−

2.372

l

V

Ni

2

+

(

a

q

)

+

2

l

e

−

→

Ni

(

s

)

−

E

θ

=

−

0.257

l

V

The standard reduction potential

E

θ

resembles the electrode's strength as an oxidizing agent and equivalently its tendency to get reduced. The reduction potential of a Platinum-Hydrogen Electrode under standard conditions (

298

l

K

,

1.00

l

kPa

) is defined as

0

l

V

for reference. [2]

A cell with a high reduction potential indicates a strong oxidizing agent- vice versa for a cell with low reduction potentials.

Two half cells connected with an external circuit and a salt bridge make a galvanic cell; the half-cell with the higher

E

θ

and thus higher likelihood to be reduced will experience reduction and act as the cathode, whereas the half-cell with a lower

E

θ

will experience oxidation and act the anode.

E

θ

(

Ni

2

+

/

Ni

)

>

E

θ

(

Mg

2

+

/

Mg

)

Therefore in this galvanic cell, the

Ni

2

+

/

Ni

half-cell will experience reduction and act as the cathode and the

Mg

2

+

/

Mg

the anode.

The standard cell potential of a galvanic cell equals the standard reduction potential of the cathode minus that of the anode. That is:

E

θ

cell

=

E

θ

(

Cathode

)

−

E

θ

(

Anode

)

E

θ

cell

=

−

0.257

−

(

−

2.372

)

E

θ

cell

=

+

2.115

Indicating that connecting the two cells will generate a potential difference of

+

2.115

l

V

across the two cells.

5 0
2 years ago
Read 2 more answers
Net ionic equation for 2AgF(aq) + k2S = Ag2S (s) + 2KF(aq)
tester [92]

Answer:

The net ionic equation shows the actual reaction more clearly and closer to reality because it writes soluble ionic compounds as the ions and then cancel the spectator ions not involved in the chemical reaction . The net ionic equation results shows the actual chemical reaction taking place.

4 0
3 years ago
What is the molarity of 2.50 mol in a 1000 ml solution? *
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Answer:

450na

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from that solution

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Choose the correct statement. The cathode is the electrode where the oxidation takes place. Both oxidation and reduction may tak
gregori [183]

Answer:

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Explanation:

Cell has three components:

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Electrolyte is usually solution of the water or other solvents in which the ions are dissolved.

<u>In electrolytic cell:</u>

Negatively charged electrode is the cathode where the process of reduction takes place.

Positively charged electrode is the anode where the process of oxidation takes place.

<u>In galvanic cell:</u>

Positively charged electrode is the cathode where the process of reduction takes place.

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<u>So, the correct answer is - The cathode is the electrode where the reduction takes place.</u>

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