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vodka [1.7K]
3 years ago
13

FInd the equation of the line

Mathematics
1 answer:
enot [183]3 years ago
6 0

Answer:

y=-3/2x+3

Step-by-step explanation:

The slope is rise over run. It rises 3 and goes back -2 so the slope is -3/2 and it crosses the y-axis at 3 so the y-intercept is 3. The slope equation is y=mx+b.

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Whole numbers are also integers. There are other integers which are the opposites of the whole numbers (−1, −2, −3, ...). These negative numbers lie to the left of 0 on the number line. Integers are the whole numbers and their opposites.

4 0
3 years ago
A machine fills containers with 35 ounces of raisins. After the containers are filled, another machine weighs them. If the conta
EleoNora [17]

Answer:

a think only thing thats close to my data

Step-by-step explanation:

7 0
2 years ago
Which table of ordered pairs represents a linear function <br> HELP FAST!!!
dalvyx [7]

The correct answer would be the 2nd option because it increases by a specific amount every X value.

6 0
3 years ago
What is the area of a triangle with vertices (3,0) (9,0) (7,6)
Nezavi [6.7K]

Answer:

The area of the triangle is of 21 units of area.

Step-by-step explanation:

The area of a triangle with three vertices (x_1,y_1),(x_2,y_2),(x_3,y_3) is given by the determinant of the following matrix:

A = \pm 0.5 \left|\begin{array}{ccc}x_1&y_1&1\\x_2&y_2&1\\1_3&y_3&1\end{array}\right|

In this question:

Vertices (3,0) (9,0) (7,6). So

A = \pm 0.5 \left|\begin{array}{ccc}3&0&1\\9&0&1\\7&7&1\end{array}\right|

A = \pm 0.5(3*0*1+0*1*7+1*9*7-0*7*1-0*9*1-3*1*7)

A = \pm 0.5*(63-21)

A = \pm 0.5*42 = 21

The area of the triangle is of 21 units of area.

5 0
2 years ago
The equation of a quadratic is =2^2+3−2and after you factorizing 2^2+3−2=0you got x = -2 and x = 1/2 and the curve crosses the y
Lelechka [254]

Given the next quadratic function:

y=2x^2+3x-2

to sketch its graph, first, we need to find its vertex. The x-coordinate of the vertex is found as follows:

x_V=\frac{-b}{2a}

where <em>a</em> and <em>b</em> are the first two coefficients of the quadratic function. Substituting with a = 2 and b = 3, we get:

\begin{gathered} x_V=\frac{-3}{2\cdot2} \\ x_V=-\frac{3}{4}=-0.75 \end{gathered}

The y-coordinate of the vertex is found by substituting the x-coordinate in the quadratic function, as follows:

\begin{gathered} y_V=2x^2_V+3x_V-2 \\ y_V=2\cdot(-\frac{3}{4})^2+3\cdot(-\frac{3}{4})-2 \\ y_V=2\cdot\frac{9}{16}+3\cdot(-\frac{3}{4})-2 \\ y_V=\frac{9}{8}-\frac{9}{4}-2 \\ y_V=-\frac{25}{8}=-3.125 \end{gathered}

The factorization indicates that the curve crosses the x-axis at the points (-2, 0) and (1/2, 0). We also know that the curve crosses the y-axis at (0,-2). Connecting these points and the vertex (-0.75, -3.125) with a U-shaped curve, we get:

6 0
1 year ago
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