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lilavasa [31]
3 years ago
6

Daniela measures her math book and records its width as 21.9 cm to the nearest tenth of a centimeter. The actual measurement of

the book’s width is 22.0 cm. What is the percent error of her measurement? Round your answer to the nearest tenth of a percent.
Mathematics
1 answer:
chubhunter [2.5K]3 years ago
6 0
The percent of error is 0.5%
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Marcos reads 3, books in 1 3/4 weeks.
Fofino [41]

Answer:

x  = \frac{12}{7}\ books

Step-by-step explanation:

Given

3\ books = 1\frac{3}{4}\ weeks

Required

Number of books in 1 week

Represent the number of books in 1 week with x.

So, we have:

3\ books = 1\frac{3}{4}\ weeks

x = 1\ week

Cross Multiply

x * 1\frac{3}{4} = 3 * 1

x * 1\frac{3}{4} = 3

Convert fraction to improper fraction

x * \frac{7}{4} = 3

Multiply through by \frac{4}{7}

x * \frac{7}{4}*\frac{4}{7} = 3 * \frac{4}{7}

x  = 3 * \frac{4}{7}

x  = \frac{12}{7}\ books

<em>Hence: 12/7 books were read in a week</em>

7 0
3 years ago
In the diagram, line x is parallel to line y
Grace [21]
True, line x is parallel to line y, according to the diagram
5 0
3 years ago
What is seven minus 4
MrRissso [65]
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6 0
3 years ago
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0/1 Gabriel used 1/3 of a liter of milk to make 2/9 of a jug of tea. How much milk is required to fill the jug?
Annette [7]

Answer:

1 1/2 liters of milk is required to fill the jug

Step-by-step explanation:

Gabriel used 1/3 of a liter of milk to make 2/9 of a jug of tea. How much milk is required to fill the jug?

From the above question, we know that:

2/9 jug of tea = 1/3 liter of milk

1 jug of tea = x

Cross Multiply

2/9 × x = 1 × 1/3

x = 1/3 /2/9

x = 1/3 ÷ 2/9

x = 1/3 × 9/2

x = 3/2

x= 1 1/2 liters of milk

Therefore, 1 1/2 liters of milk is required to fill the jug

4 0
3 years ago
Make the variable in the brackets as the subject of each of the following formulae mx + 2x = 6​
Airida [17]

Answer:

See Explanation

Step-by-step explanation:

Given

mx + 2x = 6

Required

Make the variable in bracket the subject

From the given expression, none of the variables (m and x) are in brackets.

So, I will solve for m and then solve for x

Solving for m:

mx + 2x = 6

Subtract 2x from both sides

mx = 6 - 2x

Divide both sides by x

m = \frac{6 - 2x}{x}

Solving for x:

mx + 2x = 6

Factorize

x(m+2)= 6

Divide both sides by m + 2

x = \frac{6}{m+2}

7 0
3 years ago
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