Answer:
(a) 3-ethylpentane (because the longest chain is 5 carbon atoms, and ethyl is positioned at the 3rd carbon atom)
(b) 1, 2-dimethylbutane (because two methyl is positioned at the 2nd and 3rd carbon atom)
(c) 3, 4-dimethylhexane (the longest chain here is 6 carbon atoms, and two methyl is positioned at the 3rd and 4rd carbon atom)
(d) 3-methyl 4-ethylhexane ( the longest chain is 6 carbon atoms, one methyl is positioned at the 3rd carbon atom while one ethyl is positioned at the 4rd carbon atom)
(e) and (f) are similar to the question before... and I dunno how to (g) and (h) cuz I haven't learned it
Hope that you are able to answer the rest!!
Answer:
(a) 1s2 2s1
Explanation:
Electron configurations of atoms are in their ground state when the electrons completely fill each orbital before starting to fill the next orbital.
<h3><u>
Understanding the notation</u></h3>
It's important to know how to read and interpret the notation.
For example, the first part of option (a) says "1s2"
- The "1" means the first level or shell
- The "s" means in an s-orbital
- The "2" means there are 2 electrons in that orbital
<h3><u>
</u></h3><h3><u>
Other things to know about electron orbitals</u></h3>
It important to know which orbitals are in each shell:
- In level 1, there is only an s-orbital
- In level 2, there is an s-orbital and a p-orbital
- in level 3, there is an s-orbital, a p-orbital, and a d-orbital <em>(things get a little tricky when the d-orbitals get involved, but this problem is checking on the basic concept -- not the higher level trickery)</em>
So, it's also important to know how many electrons can be in each orbital in order to know if they are full or not. The electrons should fill up these orbitals for each level, in this order:
- s-orbitals can hold 2
- p-orbitals can hold 6
- d-orbitals can hold 10 <em>(but again, that's beyond the scope of this problem)</em>
<h3><u>
Examining how the electrons are filling the orbitals</u></h3>
<u>For option (a):</u>
- the 1s orbital is filled with 2, and
- the 2s orbital has a single electron in it with no other orbitals involved.
This is in it's ground state.
<u>For option (b):</u>
- the 1s orbital is filled with 2,
- the 2s orbital is filled with 2,
- the 2p orbital has 5 (short of a full 6), and
- the 3s orbital has a single electron in it.
Because the 3s orbital has an electron, but the lower 2p before it isn't full. This is NOT in it's ground state.
<u>For option (c):</u>
- the 1s orbital is filled with 2,
- the 2s orbital has 1 (short of a full 2), and
- the 2p orbital is filled with 6
Although the 2p orbital is full, since the 2s orbital before it was not yet full, this is NOT in it's ground state.
<u>For option (d):</u>
- the 1s orbital has 1 (short of a full 2), and
- the 2s orbital is filled with 2
Again, despite that the final orbital (in this case, the 2s orbital), is full, since the 1s orbital before it was not yet full, this is NOT in it's ground state.
Answer:
Percentage yield is 41.21%
Explanation:
Equation of reaction,
N₂ + 3H₂ → 2NH₃
Actual NH3 = 6.83g
Mass of N2 = 5.77g
Theoretical yield = ?
5.77g of N2 = 6.83g of NH3
14g of N2 = xg
X = (14 × 6.83) / 5.77
X = 95.62 / 5.77
X = 16.57g of NH3
Theoretical yield of NH3 is 16.57g
Percentage yield = (actual yield / theoretical yield) × 100
% yield = (6.83 / 16.57) × 100
% yield = 0.4121 × 100
% yield = 41.21%
The percentage yield of NH3 is 41.21%
Carbonic acid refers to a weak inorganic acid, which is also known as the solution of carbon dioxide in water. It only prevails as a solution and is also known as the aerial acid, acid of air, dihydrogen carbonate, or carbon dioxide solution. It is most familiar as a constituent of the majority of the aerated drinks like soft drinks and sodas.
The carbonic acid's chemical formula is H₂CO₃. Its decomposition to water and carbon dioxide is shown by the equation:
H₂CO₃ (g) = H₂O (l) + CO₂ (g)
