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3 years ago

Sodium hydroxide (NaOH) and elemental sodium (Na)

Chemistry

1 answer:

Olegator [25]3 years ago

6 0

Answer:

If the question is which can make a buffer, then NH3, NH4Cl should be correct. Because Ammonium (NH4) is conjugate acid of NH3 so they can form an equilibrium which is basically a buffer whose purpose is to resist pH change.

Explanation:

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A match burns because of what type(s) of properties?

GalinKa [24]

It would be a chemical property

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4 years ago

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every spring has an equilibrium position which statement describe a spring at it equilibruim position?

Marina CMI [18]

The elastic potential energy is zero. The net force acting on the spring is zero. Explanation: The equilibrium position of a spring is the position that the spring has when its neither compressed nor stretched - it is also called natural length of the spring.Mar

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3 years ago

Calculate the number of C atoms in 0.183 mol of C.

Alex Ar [27]

Answer: 1.10x10²³ atoms of C

110202600000000000000000 atoms C

Explanation:The solution process is shown below.

0.183 mole C x 6.022x10²³ atoms C / 1 mole C

= 1.10x10²³ atoms C

or 110202600000000000000000 atoms C

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3 years ago

C2H6O(g) + 3O2(g) 2CO2(g) + 3H2O(g) Inside the piston of an automobile engine, 0.461 g of ethanol (C2H6O) gas reacts with 0.640

LuckyWell [14K]

Answer:

Oxygen is the limiting reactant.

Explanation:

Hello,

In this case, given the reaction:

$C_2H_6O(g) + 3O_2(g)\rightarrow 2CO_2(g) + 3H_2O(g)$

Hence, given the masses of both ethanol and oxygen, we are able to compute the available moles ethanol by:

$n_{C_2H_6O}^{available}=0.461g*\frac{1mol}{46g}=0.01mol C_2H_6O$

Next, we compute the moles of ethanol that react with the 0.640 grams of oxygen considering their 1:3 molar ratio in the chemical reaction:

$n_{C_2H_6O}^{consumed\ by\ O_2}=0.64gO_2*\frac{1molO_2}{32gO_2}*\frac{1molC_2H_6O}{3molO_2} =0.0067molC_2H_6O$

In such a way, since there are 0.01 available moles of ethanol but just 0.0067 moles are reacting, we evidence ethanol is in excess, therefore the oxygen is the limiting reactant.

Best regards.

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3 years ago

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How many seconds in the school year? (One school year is 180 days long.) Please show your work, and report your answer with the

Masja [62]

Answer:

259200

Explanation:

multiply 180×24×60

259,200 seconds

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3 years ago

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