A valence electron structure would be like this 1s^2 2s^2 2p^6 etc
1s^2 would be 2, 2s^2 would be 4, 2p^6 would be 12 and so on and so forth.
Answer:
Explanation:
density is mass over volume
Mass = 163 grams
Volume = 58.5 - 50.0 = 8.5
density = 163 / 8.5
density = 19.176
To 3 figures that 19.2 grams / mL
Answer:
The unknown NaOH base has a concentration of 0.636M
Explanation:
<u>Step 1:</u> the balanced equation
NaOH + HCl → NaCl + H2O
This means for 1 mole of NaOH consumed there is 1 mole of HCl needed to produce 1 mole of NaCl and 1 mole of H2O
<u>Step 2</u>: Calculate moles of HCl used
Number of moles = Concentration * volume = 0.5M * 25*10^-3 L =0.0125 moles
<u>Step 3</u>: Calculate moles of NaOH
Since the mole ratio for HCl and NaOH is 1:1 this means we have 0.0125 moles of NaOH for 0.0125 moles of HCl
<u>Step 4:</u> Calculate Concentration of the unknown NaOH base
Concentration = Number of moles / Volume
Volume of NaOH = 24.64-5 =19.64 mL = 0.01964 L
Concentration = 0.0125/0.01964 = 0.636 M
The unknown NaOH base has a concentration of 0.636M
Explanation:
Please find the Measures of Center and construct a histogram AND find the 5-number summary and construct a box-n-whisker plot for the numbers below.
To answer the question above, let us a basis of the 1000 mL or 1 L.
volume = (0.9928 g/mL)(1000mL) = 992.8 g
Then, determine the mass of the alcohol by multiplying the total mass by the decimal equivalent of 5%.
mass of alcohol = 0.05(992.8 g) = 49.64 g
Then, determine the number of moles of ethyl alcohol by dividing the mass of alcohol by the molar mass (46 g/mol).
n = 49.64 g/ (46 g/mol) = 1.08 mol
Then, divide the number of moles by the volume (our basis is 1 L)
molarity = 1.08 mol/ 1 L = 1.08 M
