Explanation:
The given chemical reaction is:
The relation between Eo cell and Keq is shown below:
The value of Eo cell is:
Br- undergoes oxidation and I2 undergoes reduction.
Reduction takes place at cathode.
Oxidation takes place at anode.
Hence,
F=96485 C/mol
n=2 mol
R=8.314 J.K-1.mol-1
T=298K
Substitute all these values in the above formula:
Answer:
Keq=6.13x10^33
The product of reduction of ethyl 4-oxobutanoate with sodium borohydride in ethanol at room temperature for 30 minutes is ethyl 4- hydroxybutanoate .
Sodium borohydride is a relatively selective reducing agent Ethanolic solutions of Sodium borohydride reduces aldehyde , and ketone , in the presence of acid chloride , ester , epoxide , lactones , acids , nitriles , nitro groups.
The sodium borohydride does not reduce ester group because sodium borohydride is not strong enough and the electrophilicity at carbony carbon of ester is not more as compare toaldehyde , and ketone
The product of reduction of ethyl 4-oxobutanoate with sodium borohydride in ethanol at room temperature for 30 minutes is ethyl 4- hydroxybutanoate .
to learn more about sodium borohydride and ethanol click here ,
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How many grams Carbon in 1 moles? The answer is 12.0107.
<span>We assume you are converting between </span>grams Carbon<span> and </span>mole.
You can view more details on each measurement unit:
molecular weight of Carbon<span> or </span>moles
<span>The molecular formula for Carbon is </span>C.
<span>The SI base unit for </span>amount of substance<span> is the mole.</span>
1 grams Carbon is equal to 0.0832590939745 mole.
Note that rounding errors may occur, so always check the results.
Use this page to learn how to convert between grams Carbon and mole.
<span>Type in your own numbers in the form to convert the units!
</span>
A) solid
b)liquid
c)liquid
d)gas
Answer:
yes I think that they are correct
