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Kruka [31]
3 years ago
12

Suppose that you buy a two-year 8% bond at its face value.

Mathematics
1 answer:
Juliette [100K]3 years ago
4 0

Answer:

Real Rate of Return = 4.9%  and Nominal rate = 0.08 or 8%

Real Rate of Return = 2.9%  and Nominal rate = 0.081 or 8.1%

real rate = 5 %   and Nominal rate = 0.0815 or 8.15%

real rate = 3%  and Nominal rate = 0.0815 or 8.15%

Step-by-step explanation:

given data

time period = 2 year

Coupon rate = 8% =  0.08

Inflation rate 1st year = 3% =  0.03

Inflation rate 2nd year = 5% =  0.05

solution

we get here Real Rate of Return  that is express as

Real Rate of Return = (Coupon Rate - Inflation rate) ÷ (1+Inflation rate)   .........1

so that here 1st year Real return  will be

Real Rate of Return = (0.08 - 0.03) ÷ (1+0.03)

solve it we get

Real Rate of Return = 4.9%

and

(1 + nominal rate) = (1 + real rate) × (1 + inflation rate)     ............2

(1 + nominal rate) = (1 + 0.049) × (1 + 0.03)

Nominal rate = 0.08 or 8%

and

for 2nd year Real return  will be

Real Rate of Return = (0.08 - 0.05) ÷ (1+0.05)

solve it

Real Rate of Return = 2.9%

and

(1 + nominal rate) = (1 + real rate) × (1 + inflation rate)     ............3

(1 + nominal rate) = (1 + 0.029) × (1 + 0.05)

Nominal rate = 0.081 or 8.1%

and

now for the bond Treasury Inflation-Protected Securities, we get real and nominal return that is

for 1st year

Real rate = Coupon rate - Inflation     ...............4

Real rate = 0.08 - 0.03

real rate = 0.05

and

(1 + nominal rate) = (1 + real rate) × (1 + inflation rate)     ................5

(1 + nominal rate) = (1 + 0.05) × (1 + 0.03)

so

Nominal rate = 0.0815 or 8.15%

and for 2nd years  it will be

Real rate = Coupon rate - Inflation      ....................6

Real rate = 0.08 - 0.05

real rate = 0.03

and

(1 + nominal rate) = (1 + real rate) × (1 + inflation rate)     ...................7

(1 + nominal rate) = (1 + 0.03) × (1 + 0.05)

so

Nominal rate = 0.0815 or 8.15%

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Answer:

3*∑ (1/2)^n = 6

Step-by-step explanation:

We have the summation from n = 1 to n = ∞, for:

∑ 3/(2)^(n - 1)

We know that the summation between k = 0, and k = N - 1 for:

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if we have the summation between k = 0 and k = ∞ - 1 = ∞

(here we used that ∞ is really big, then ∞ - 1 = ∞)

In the numerator we will have the term r^∞, if 0 < r < 1, then r^∞ = 0.

Then if we assume that 0 < r < 1 we can write:

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In our case, we can rewrite our summation as:

3*∑ (1/2)^n

for n = 0 to  n = ∞

You can see that i changed the limits for n, this does not really matter because we are summing between a number and infinity, the only thing you need to take care is that now the power is n, instead of (n - 1)

Then we have r = (1/2) which is clearly smaller than 1.

then (1/2)

Then this summation is equal to:

3*∑ (1/2)^n = 3*( 1/(1 - 1/2)) = 3*( 1/( 2/2 - 1/2)) = 3*( 1/(1/2)) = 3*2 = 6

3*∑ (1/2)^n = 6

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A gumball machine has just been filled with 50 black, 150 white, 100 red and 100 yellow gum balls that have been thoroughly mixe
Andrew [12]
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4 years ago
Which expression represents a number n increased by 18
liraira [26]

Answer:

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Step-by-step explanation:

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4 0
2 years ago
involving the election of officers on a committee. Assume that the committee consists of 14 members including Tasha. The same th
Yanka [14]

Answer:

There are 364 ways of filling the offices.

Step-by-step explanation:

In this case, the order of filling of the offices does not matter, so, we can figure out the different ways of filling the offices by using the combination formula:

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where n=14 (number of members)

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C^{14} _{3}=\frac{14!}{(14-3)!3!}=\frac{14*13*12*11*10*9*8*7*6*5*4*3*2*1}{(11*10*9*8*7*6*5*4*3*2*1)*(3*2*1)}=\frac{14*13*12}{3*2*1} =364

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IRISSAK [1]

Answer:

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