Question

URGENT, DUE VERY SOON

Answer 1

Answer:

1. Plot the point (–2,4).

2. From that point, count left 3 units and down 1 unit and plot a second point.

3. Draw a line through the two points.

Step-by-step explanation:

Given:

The equation is: $y-4=\frac{1}{3}(x+2)$

Express this in the standard form, $y=mx+b$

Where, $m$ is the slope of the line and $b$ is the y-intercept.

$y-4=\frac{1}{3}((x+2)\\y=\frac{1}{3}((x+2)+4\\y=\frac{1}{3}x+\frac{2}{3}+4\\y=\frac{1}{3}x+\frac{14}{3}$

So, the slope is $\frac{1}{3}$ and y-intercept is $\frac{14}{3}$.

Now, for $x=-2,y=\frac{1}{3}\times -2+\frac{14}{3}=4$

So, first we plot the point $(-2,4)$.

Since, the slope is $\frac{1}{3}$, we have to move 3 units to left and then 1 unit down to plot a second point.

Slope is positive, therefore, we have to move left and then down

Lastly, we have to draw a line passing through these two points to graph the equation $y-4=\frac{1}{3}(x+2)$.