Answer:
105 m/s
Explanation:
Given that the speed of train A, = 45 m/s from west to east.
Speed of train B, = 60 m/s from east to west.
Train B is moving in the opposite direction with respect to the speed of train A. Assuming that the speed from east to west direction is positive.
So, the speed of train A from east to west= - 45 m/s
The speed of train B w.r.t train A m/s
Hence, the speed of train B w.r.t train A is 105 m/s from east to west.
5 km northeast. Left and up would make northeast
Answer:
The amplitude measures the height of the crest of the wave from the midline. The wavelength measures the horizontal distance between cycles.
Explanation:
Answer:
f1 = 58.3Hz, f2 = 175Hz, f3 = 291.6Hz
Explanation:
lets assume speed of sound is 350 m/s.
frequencies of a standing wave modes of an open-close tube of length L
fm = m(v/4L)
where m is 1,3,5,7......
and fm = mf1
where f1 = fundamental frequency
so therefore: f1 = 350 x 4 / 1.5
f1 = 58.3Hz
f2 = 3 x 58.3
f2 = 175Hz
f3 = 5 x 58.3
f3 = 291.6Hz
Pretty sure it’s false....................