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MissTica
3 years ago
10

If the total momentum for a system is the same before and after the collision, we say that momentum is conserved. If momentum we

re conserved, what would be the ratio of the total momentum after the collision to the total momentum before the collision?
Physics
1 answer:
andrew-mc [135]3 years ago
5 0

Answer:

Ratio = 1:1

Explanation:

P_{i} = initial momentum of the system

P_{f} = final momentum of the system

For the momentum to be conserved , final total momentum must be equal to initial total momentum, so we have

P_{f} = P_{i}

Dividing both side by P_{i} , we get

\frac{P_{f}}{P_{i}} = \frac{P_{i}}{P_{i}} \\\frac{P_{f}}{P_{i}} = 1\\

hence

Ratio = 1

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The Atwood’s machine shown consists of two blocks of mass m1 and m2 that are connected by a light string that passes over a pull
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(A) For the system consisting of the two blocks, the change in the kinetic energy of the system is equal to work done by gravity on the system.

(D) For the system consisting of the two blocks, the pulley and the Earth, the change in the total mechanical energy of the system is zero.

<h3 /><h3>The given parameters:</h3>
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  • Height of block 1 above the ground, = h1
  • Height of block 2 above the ground = h2

The total initial mechanical energy of the two block system is calculated as follows;

m_1gh_1 + \frac{1}{2} m_1v_1_i^2 = m_2gh_2 + \frac{1}{2} m_2v_2_i^2\\\\m_1gh_1 + 0 = m_2gh_2 + 0\\\\m_1gh_1 = m_2gh_2\\\\m_1gh_1 - m_2gh_2 = 0

When the block m2 reaches the ground the block m1 attains maximum height and the total mechanical energy at this point is given as;

m_1g(h_1 + h_2) + K.E_1 = \frac{1}{2}m_2v_{max}^2 + P.E_2\\\\m_1g(h_1 + h_2 ) -PE_2 = \frac{1}{2}m_2v_{max}^2 - K.E_1\\\\m_1g(h_1 + h_2 )  - 0= \frac{1}{2}m_2v_{max}^2 - 0\\\\m_1g(h_1 + h_2 )  = \frac{1}{2}m_2v_{max}^2\\\\W = \frac{1}{2}m_2v_{max}^2

Thus, we can conclude the following before the block m2 reaches the ground;

  • For the system consisting of the two blocks, the pulley and the Earth, the change in the total mechanical energy of the system is zero.
  • For the system consisting of the two blocks, the change in the kinetic energy of the system is equal to work done by gravity on the system.

Learn more about conservation of mechanical energy here: brainly.com/question/332163

5 0
3 years ago
A 5 kg object moving to the right at 4 m/s collides inelastically with a 5 kg object
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p = mv (7.1)

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Answer:

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