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2 years ago

12

What type of wave has crests and troughs?

1 answer:

sergeinik [125]2 years ago

6 0

Answer:

tidal wave

Explanation:

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This is lettle alchemy 2, I need a life, and I got all this in 2 days, more like 16 hours

Alex_Xolod [135]

Answer: I don't know you But i am proud good job

fun game isn't it xD

Explanation:

6 0

2 years ago

Two protons, starting several meters apart, are aimed directly at each other with speeds of 2.00 * 105 m>s, measured relative

victus00 [196]

Explanation:

Since, the two protons are at the initial state of point a and point b. Hence, total mechanical energy at point a and point b is as follows.

$U_{a} + K_{a} = U_{b} + K_{b}$

or, $K_{a} = U_{b}$

where, $K_{a}$ = kinetic energy of two protons

So, $2(\frac{1}{2}mV^{2}_{a}) = \frac{1}{4 \pi \epsilon_{o}} \frac{|e|^{2}}{r_{b}}$

$r_{b} = \frac{1}{4 \pi \epsilon_{o}} \frac{e^{2}}{mV^{2}_{a}}$

Putting the given values into the above formula we will calculate the value of $r_{b}$ as follows.

$r_{b} = \frac{1}{4 \pi \epsilon_{o}} \frac{e^{2}}{mV^{2}_{a}}$

= $(9.0 \times 10^{9} Nm^{2}/C^{2} \frac{(1.602 \times 10^{-19}^{2} C}{1.67 \times 10^{-27} kg \times 2 \times 10^{5}}$

= $3.45 \times 10^{-12} m$

Now, we will calculate the maximum electric field as follows.

F = $\frac{1}{4 \pi \epsilon_{o}} \frac{|e|^{2}}{r^{2}_{b}}$

= $9.0 \times 10^{9} Nm^{2}/C^{2} \frac{(1.602 \times 10^{-19}C)^{2}}{3.45 \times 10^{-12}}$

= $0.194 \times 10^{-4} N$

Therefore, we can conclude that the maximum electric force that these protons will exert on each other is $0.194 \times 10^{-4} N$ .

7 0

3 years ago

You are traveling at 55 mi/h along the x-axis relative to a straight, level road and pass a car that is traveling at 45 mi/h. Th

Alik [6]

Answer:

10 mph

Explanation:

55 - 45 = 10 mph

4 0

2 years ago

A cylindrical tank has a tight-fitting piston that allows the volume of the tank to be changed. The tank originally contains 0.1

Shkiper50 [21]

Answer:

0.10013 atm

Explanation:

Applying Boyle's Law,

P'V' = PV................... Equation 1

Where P' = Initial pressure of air, V' = Initial volume of air, P = Final pressure of air, V = Final volume of air.

make P the subject of the equation

P = P'V'/V..................... Equation 2

Given: P' = 0.355 atm, V' 0.110 m³, V = 0.390 m³

Substitute into equation 2

P = 0.355(0.11)/0.39

P = 0.10013 atm.

5 0

3 years ago

A solar panel measures 0.57 m by 1.3 m. In direct sunlight, the panel delivers 6.6 A at 6 V. If the intensity of sunlight is 300

zheka24 [161]

Answer:

efficiency of solar panel is 18%

Explanation:

Energy received by the sunlight is given as

$Power = intensity \times area$

here we know the dimensions of the plate as

$L = 0.57 m$

$W = 1.3 m$

now we have

$Area = (0.57)(1.3) m^2$

$A = 0.741 m^2$

now the power received by the sun light is given as

$P_1 = 0.741(300) = 222.3 W$

now the output power due to solar panel is given as

$P_{out} = V i$

$P_{out} = (6.6 A)(6 V)$

$P_{out} = 39.6 Watt$

now the efficiency is given as

$\eta = \frac{P_{out}}{P_{in}}$

$\eta = \frac{39.6}{222.3}$

$\eta = 0.18$

8 0

3 years ago