Answer:
besides a reduction in friction, the only way to increase the amount of work output of a machine is to Increase the work input
i
Explanation:
Answer:
C. 39 m/s
Explanation:
First we need to calculate the total force required to move the train along the inclined plane. So, it is clear that the work done will be equal to the component of the weight that is parallel to the inclined plane, because there is no frictional force present:
Force = F = mg Sin θ
where,
m = mass of train = 3.3 x 10⁶ kg
g = 9.8 m/s²
θ = Angle of Inclination = 0.64°
Therefore,
F = (3.3 x 10⁶ kg)(9.8 m/s²)Sin 0.64°
F = 3.612 x 10⁵ N
Now, the formula for power is:
P = FV
V = P/F
where,
V = Velocity of Train = ?
P = Power of Engine = 14 MW = 1.4 x 10⁷ W
Therefore,
V = 1.4 x 10⁷ W/3.612 x 10⁵ N
V = 38.75 m/s
which is approximately equal to:
<u>C. 39 m/s</u>
Energy (C) is fully described by its magnitude.
There's nothing else about it to measure.
The other four things on the list are all vectors.
They need directions to go along with their magnitudes.
Answer:
list of spring in order of increasing spring constant is given by,
W, Y, X, Z
Explanation:
Spring W:
Magnitude of Force applied on the spring is given by,
F = k x
Where, F = force applied
k = spring constant
x displacement
k = F/x
k = 20 / 0.5
k = 40 N/m
Spring X:
Magnitude of Force applied on the spring is given by,
F = k x
Where, F = force applied
k = spring constant
x displacement
k = F/x
k = 60 / 0.3
k = 200 N/m
Spring Y:
Magnitude of Force applied on the spring is given by,
F = k x
Where, F = force applied
k = spring constant
x displacement
k = F/x
k = 40 / 0.4
k = 100 N/m
Spring Z:
Magnitude of Force applied on the spring is given by,
F = k x
Where, F = force applied
k = spring constant
x displacement
k = F/x
k = 50 / 0.1
k = 500 N/m
Thus, list of spring in order of increasing spring constant is given by,
W, Y, X, Z
