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Maru [420]
3 years ago
12

40 POINTS I’ve been stuck on this for hours please help :(

Physics
2 answers:
kondaur [170]3 years ago
8 0

  ..................................         uh ya

Norma-Jean [14]3 years ago
7 0

Answer:

Explanation:

Particle         Relative Mass       Charge               Location

Proton             1                            +                        Nucleus

Electron          0                            -                        Outside rings (not nucleus)

Neutron.         1                            No Charge        Nucleus

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An 80-kg quarterback jumps straight up in the air right before throwing a 0.43-kg football horizontally at 15 m/s . How fast wil
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Answer:

a

The speed of the quarterback backward is v_q =  0.08 \ m/s

b

Known are

 m_Q , m_B , (v_{Bx})_i  (v_{Qx})_f, (v_{Bx})_f

Unknown

   (v_{Qx})_f

Explanation:

From the question we are told that

   The mass of the quarterback is m_Q =  80 \ kg

    The mass of the ball is m_B =  0.43 \ kg

     The speed of the ball is  v_{B x}=  15 \ m/s

The law of momentum conservation can be mathematically represented as

       m_Q u_{Qx} + m_Bu_{Bx}  =  - m_{Q} v_{Qx} + m_B v_{Bx}

Now at initial both ball and quarterback are at rest and the negative sign signify that the quarterback moved backwards after throwing the ball

  So

       m_Q v_{Qx} =  m_B v_ {Bx}

=>     v_{Qx} =  \frac{m_Bv_{Bx}}{m_Q}

substituting values

        v_q =  \frac{0.43 * 15}{80}

       v_q =  0.08 \ m/s

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