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3 years ago

A 5 kg object moving to the right at 4 m/s collides inelastically with a 5 kg object

Physics

1 answer:

skad [1K]3 years ago

5 0

Answer:

The linear momentum of a particle with mass m moving with velocity v is defined as

p = mv (7.1)

Linear momentum is a vector . When giving the linear momentum of a particle you must

specify its magnitude and direction. We can see from the definition that its units must be

kg·m

. Oddly enough, this combination of SI units does not have a commonly–used named so

we leave it as kg·m

The momentum of a particle is related to the net force on that particle in a simple way;

since the mass of a particle remains constant, if we take the time derivative of a particle’s

momentum we find

dt = m

dt = ma = Fnet

so that

Fnet =

dt (7.2)

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A current of 1.41 A in a long, straight wire produces a magnetic field of 5.61 uT at a certain distance from the wire. Find

pshichka [43]

Answer:

0.050 m

Explanation:

The strength of the magnetic field produced by a current-carrying wire is given by

$B=\frac{\mu_0 I}{2\pi r}$

where

$\mu_0=4\pi \cdot 10^{-7} H/m$ is the vacuum permeability

I is the current in the wire

r is the distance from the wire

And the magnetic field around the wire forms concentric circles, and it is tangential to the circles.

In this problem, we have:

$I=1.41 A$ (current in the wire)

$B=5.61\mu T=5.61\cdot 10^{-6} T$ (strength of magnetic field)

Solving for r, we find the distance from the wire:

$r=\frac{\mu_0 I}{2\pi B}=\frac{(4\pi \cdot 10^{-7})(1.41)}{2\pi (5.61\cdot 10^{-6})}=0.050 m$

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3 years ago

An electric toy with a resistance of 2.50 Ω is operated by a 3.00-V battery. (a) What current does the toy draw? (b) Assuming th

Leno4ka [110]

Answer:

a) The current is i = 1.2 A

b) The charge is Q = 17280 C

c) The energy is E = 43200 J

Explanation:

a) The current is given by the ohm's law wich is:

i = V/R = 3/2.5 = 1.2 A

b) Since the charge is steady we can use the following equation to find the charge amount in that time:

i = Q/t

Q = t*i

Where t is in seconds, so we have 4h * 3600 = 14400 s

Q = 1.2*14400 = 17280 C

c) The energy is the power delivered to the toy multiplied by the time:

P = 1.2*2.5 = 3 W

E = P*t = 3*14400 = 43200 J

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Answer:

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Explanation:

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