All categories

2 years ago

A 5 kg object moving to the right at 4 m/s collides inelastically with a 5 kg object

Physics

1 answer:

skad [1K]2 years ago

5 0

Answer:

The linear momentum of a particle with mass m moving with velocity v is defined as

p = mv (7.1)

Linear momentum is a vector . When giving the linear momentum of a particle you must

specify its magnitude and direction. We can see from the definition that its units must be

kg·m

. Oddly enough, this combination of SI units does not have a commonly–used named so

we leave it as kg·m

The momentum of a particle is related to the net force on that particle in a simple way;

since the mass of a particle remains constant, if we take the time derivative of a particle’s

momentum we find

dt = m

dt = ma = Fnet

so that

Fnet =

dt (7.2)

You might be interested in

What acceleration is imparted to a football when the player kicked it with a force of 25 N? mass of football=0.40 kg

Bond [772]

Force = mass x acceleration

25N = 0.40kg x acceleration
25N/0.40kg = acceleration

acceleration = 62.5 N/kg
N/kg is the equivalent of m/s²

So your acceleration is 62.5 meters per second squared

6 0

3 years ago

A rifle of mass 2 kg is horizontally suspended by a pair of strings so that recoil can be measured. The rifle fires a bullet of

aliya0001 [1]

Answer: 1m/s

Explanation: according to the law of conservation of linear momentum in an isolated system, the momentum of the gun equals that of the bullet.

Mathematically

Mb×Vb = Mg×Vg

Where Mb = mass of bullet = 1/100 = 0.01 kg

Vb = velocity of bullet = 200 m/s

Mg = mass of gun = 2kg

Vg = recoil velocity of gun =?

0.01×200 = 2×Vg

Vg = 0.01×200/2

Vg = 0.01×100

Vg = 1m/s

3 0

3 years ago

A hot air balloon contains 85,000 moles of air. To what temperature must the

Oksi-84 [34.3K]

Answer:

B is the best answer for this question

8 0

3 years ago

An explorer is caught in a whiteout (in which the snowfall is so thick that the ground cannot be distinguished from the sky) whi

Brrunno [24]

Answer:

The explorer should travel to reach base camp to 5.02 Km at 4.28° south of due west.

Explanation:

Using trigonometric function like Sen(Ф), Cos(Ф) and Tan(Ф) we can get distance and direction that the explorer should travel to reach base camp. When we discompound the vector $X = 7.8*Cos(50) = 5.01 Km$ y $y = 7.8 * Sen (50) - 5.6 = 5.975 - 5.6 (Km) = 0.375 (Km)$ so that $Tan (\alpha ) = \frac{0.375}{5.01} = 4.28$ ; $\alpha = Arctang (\frac{0.375}{5.01}) = 4.28 (degree)$ to get how far we use Pythagorean theorem so $R^{2} = x^{2}+y^{2}$ so that $R=\sqrt{0.375^{2}+5.01^{2} } =5.02 (Km)$