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natita [175]
3 years ago
8

Samuel worked at a beach stand over the summer. He worked 6 hours a day 4 days a week. He earned $7.50 per hour how much money d

id he make in one week?
Mathematics
1 answer:
Nata [24]3 years ago
3 0
Total earning in the summer = $1440
Step-by-step explanation:
Earning per hour for Samuel = $7.50
No. of hours worked in a day = 6
Earning for a day = Earning per hour for Samuel *No. of hours worked in a day
Earning for a day = $7.50 *6 = $45
___________________________________________________
No of days worked in a week by Samuel = 4
Earning for week = Earning for a day *No of days worked in a week by Samuel
Earning for week = $45*4 = $180
_____________________________________________________
No. of weeks worked in summer = 8
Total earning in the summer = Earning for week *No. of weeks worked in summer
Total earning in the summer = $180*8 = $1440 (Answer)

*NOT MY ANSWER SOMEONE ALREADY ANSWERED THIS***
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Step-by-step explanation:

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The probability that two people have the same birthday in a room of 20 people is about 41.1%. It turns out that
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Answer:

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X \sim Binom(n=20, p=0.411)

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And then:

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Step-by-step explanation:

Previous concepts

A Bernoulli trial is "a random experiment with exactly two possible outcomes, "success" and "failure", in which the probability of success is the same every time the experiment is conducted". And this experiment is a particular case of the binomial experiment.

The binomial distribution is a "DISCRETE probability distribution that summarizes the probability that a value will take one of two independent values under a given set of parameters. The assumptions for the binomial distribution are that there is only one outcome for each trial, each trial has the same probability of success, and each trial is mutually exclusive, or independent of each other".

The probability mass function for the Binomial distribution is given as:  

P(X)=(nCx)(p)^x (1-p)^{n-x}  

Where (nCx) means combinatory and it's given by this formula:  

nCx=\frac{n!}{(n-x)! x!}  

Solution to the problem

Part a

Let X the random variable of interest, on this case we know that:

X \sim Binom(n=20, p=0.411)

This random variable represent that two people have the same birthday in just one classroom

Part b

We can find first the probability that one or more pairs of people share a birthday in ONE class. And we can do this:

P(X\geq 1 ) = 1-P(X

And we can find the individual probability:

P(X=0) = (20C0) (0.411)^0 (1-0.411)^{20-0}=0.0000253

And then:

P(X\geq 1 ) = 1-P(X

And since we want the probability in the 3 classes we can assume independence and we got:

P= 0.99997^3 = 0.9992

So then the probability that one or more pairs of people share a birthday in your three classes is approximately 0.9992

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