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kaheart [24]
2 years ago
7

2x+14=22 what is the solution

Mathematics
1 answer:
Kruka [31]2 years ago
4 0

2x+14=22

Move +14 to the other side. Sign changes from +14 to -14.

2x+14-14=22-14

2x=8

Divide by 2 for both sides.

2x/2=8/2

Cross out 2 and 2 , divide by 2 and becomes: 1*1*x=x

x=4

Answer: x=4

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Alexxandr [17]

Answer:

ready

Step-by-step explanation:

8 0
2 years ago
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The area of a triangle is 150 cm^2. If the area of a triangle is given by the formula A=0/5b*h, write an equation which relates
taurus [48]

Answer:

Step-by-step explanation:

If the area of a triangle is 150cm^2, the formula would look like:

150=0.5b*h

So, if we were to solve for the base in terms of h, we'd simply divide both sides by 0.5b getting:

(150)/(0.5b)=h

which simplifies to

h=300b

4 0
3 years ago
Please help me on this!
Kipish [7]

Answer:

<u>B. The amount of money she saves each week </u> is 100% the correct answer

Step-by-step explanation:

325 is the amount she had

125 is the amoun she adds every week to her savings

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6 0
1 year ago
Read 2 more answers
What are the x-intercepts of y=2x^2+6x-20?
NISA [10]

Answer:

the x-intercepts are -5 and 2

Step-by-step explanation:

y=2x^2+6x-20

x-intercept is when y is set equal to zero

So, y = 0

0 = 2x^2+6x-20

2x^3+6x-20 = 0\\Taking \ 2 \ common\\2(x^2+3x-10) = 0\\Dividing \ both \ sides \ by \ 2\\x^2+3x-10 = 0\\Using \ mid\ term \ break \ formula\\x^2+5x-2x-10 = 0\\x(x+5)-2(x+5)=0\\Taking \ (x+5) \ common\\(x+5)(x-2) = 0

Either,

x+5 = 0    <u><em> OR </em></u>    x-2 = 0

x = -5       <u><em> OR  </em></u>     x = 2

So, the x-intercepts are -5 and 2

7 0
2 years ago
Read 2 more answers
RS=2x-8, ST = 11, RT = x+10
ziro4ka [17]

Answer:

Equation~=~\Large\boxed{2x+3=x+10}

x~=~\Large\boxed{7}

RS~=~\Large\boxed{6}

RT~=~\Large\boxed{17}

Step-by-step explanation:

<u>Given information</u>

RS=2x-8

ST=11

RT=x+10

<u>Derived expression from the given information</u>

<em>Presumably, I think this is a combination of segments</em>

RS+ST=RT

<u>Substitute values into the given expression</u>

(2x-8)+(11)=(x+10)

<u>Combine like terms</u>

<em>The following is the expression</em>

\Large\boxed{2x+3=x+10}

<u>Subtract 3 on both sides</u>

2x+3-3=x+10-3

2x=x+7

<u>Subtract x on both sides</u>

2x-x=x+7-x

\Large\boxed{x=7}

<u>Substitute the x value into corresponding expressions to determine the final value</u>

RS=2x-8=2(7)-8=14-8=\Large\boxed{6}

RT=x+10=(7)+10=\Large\boxed{17}

Hope this helps!! :)

Please let me know if you have any questions

3 0
1 year ago
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