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2 years ago

Given the equations x + y = 20 and x - y = 8, which values of x and y

Mathematics

1 answer:

hammer [34]2 years ago

6 0

Answer:

x = 14 and y = 6

Step-by-step explanation:

To find the solution to this problem, we plug in the values of x and y from each answer choice and simplify.

(11) + (9) = 20. 20 = 20.
(11) - (9) = 20. 2 ≠ 8.

(9) + (11) = 20. 20 = 20
(9) - (11) = 20. -2 ≠ 8.

(14) + (6) = 20. 20 = 20.
(14) - (6) = 8. 8 = 8.

(6) + (14) = 20. 20 = 20
(6) - (14) = 8. -8 ≠ 8.

Therefore, the correct answer is x = 14 and y = 6.

Have a lovely rest of your day/night, and good luck with your assignments! ♡

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$\green{\large\underline{\sf{Solution-}}}$

Given expression is 

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can be rewritten as

$\rm \: = \: \dfrac{5 \times { {(5}^{2} )}^{n + 1} - {5}^{2} \times {5}^{2n} }{5 \times {5}^{2n + 3} - {( {5}^{2} )}^{n + 1} }$

We know,

$\purple{\rm :\longmapsto\:\boxed{\tt{ {( {x}^{m} )}^{n} \: = \: {x}^{mn}}}} \\$

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$\purple{\rm :\longmapsto\:\boxed{\tt{ \: \: {x}^{m} \times {x}^{n} = {x}^{m + n} \: }}} \\$

So, using this identity, we

$\rm \: = \: \dfrac{5 \times {5}^{2n + 2} - {5}^{2n + 2} }{{5}^{2n + 3 + 1} - {5}^{2n + 2} }$

$\rm \: = \: \dfrac{{5}^{2n + 2 + 1} - {5}^{2n + 2} }{{5}^{2n + 4} - {5}^{2n + 2} }$

can be further rewritten as

$\rm \: = \: \dfrac{{5}^{2n + 2 + 1} - {5}^{2n + 2} }{{5}^{2n + 2 + 2} - {5}^{2n + 2} }$

$\rm \: = \: \dfrac{ {5}^{2n + 2} (5 - 1)}{ {5}^{2n + 2} ( {5}^{2} - 1)}$

$\rm \: = \: \dfrac{4}{25 - 1}$

$\rm \: = \: \dfrac{4}{24}$

$\rm \: = \: \dfrac{1}{6}$

Hence, 

$\rm :\longmapsto\:\boxed{\tt{ \dfrac{5 \times {25}^{n + 1} - 25 \times {5}^{2n} }{5 \times {5}^{2n + 3} - {25}^{n + 1} } = \frac{1}{6} }}$

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