Answer:
4.14 eV
Explanation:
f = 1.0 ×10^15 Hz
h= 6.63×10^-34 J s ( this is called PLANCK 'S CONSTANT)
ENEGY = E = ?
E = hf ( THIS IS FORMULA FOR ENERGY OF ONE QUANTA OR ONE PHOTON )
E= 6.63×10^-34×1.0 ×10^15
E = 6.63×10^-19 J
As 1eV = 1.6×10^-19 J so changing energy in eV from joules we will divide energy by 1.6×10^-19
hence E in eV = 6.63×10^-19/(1.6×10^-19)
E = 4.14 eV
Answer: B. I hope you get this right.
Answer:
Decrease
Explanation:
I = Current = 3.7 A
e = Charge of electron = 
n = Conduction electron density in copper = 
= Drift velocity of electrons
r = Radius = 1.23 mm
Current is given by
The drift speed of the electrons is
From the equation we can see the following
So, if the number of conduction electrons per atom is higher than that of copper the drift velocity will decrease.
Answer:
I would hope they can change this question
Answer:
true
Hoped this helped(⁄ ⁄>⁄ ▽ ⁄<⁄ ⁄)
