B. <span>much precipitation </span>
Answer:
![\theta=40^0](https://tex.z-dn.net/?f=%5Ctheta%3D40%5E0)
Explanation:
The magnitude of the magnetic force is
![F_m=evB\sin\theta](https://tex.z-dn.net/?f=F_m%3DevB%5Csin%5Ctheta)
To find the angle, we make
subject of the formula
![\implies \sin\theta=\frac{F_m}{evB}=\frac{7.20\times 10^{-13}}{1.6\times 10^{-19}\times 3.90\times 10^6\times 1.80}](https://tex.z-dn.net/?f=%5Cimplies%20%5Csin%5Ctheta%3D%5Cfrac%7BF_m%7D%7BevB%7D%3D%5Cfrac%7B7.20%5Ctimes%2010%5E%7B-13%7D%7D%7B1.6%5Ctimes%2010%5E%7B-19%7D%5Ctimes%203.90%5Ctimes%2010%5E6%5Ctimes%201.80%7D)
![\implies \sin\theta=0.641025641](https://tex.z-dn.net/?f=%5Cimplies%20%5Csin%5Ctheta%3D0.641025641)
![\therefore \theta=\sin^{-1}=39.8683^0\\\implies \theta\approxeq 40^0](https://tex.z-dn.net/?f=%5Ctherefore%20%5Ctheta%3D%5Csin%5E%7B-1%7D%3D39.8683%5E0%5C%5C%5Cimplies%20%5Ctheta%5Capproxeq%2040%5E0)
Y - yo = Vo*t - g * (t^2) / 2
Vo = - 9.0 m/s
t = 0.50 s
=> y - yo = -9.0 m/s * 0.5 s - 9.8 m/s^2 * (0.5s)^2 / 2 = - 4.5m - 1.225m = - 5.725 m.
Answer: option c) - 5.7
Answer:
5 m/s2
Explanation:
The total acceleration of the circular motion is made of 2 components: centripetal acceleration and linear acceleration of 4 m/s2. They are perpendicular to each other.
The centripetal acceleration is the ratio of instant velocity squared and the radius of the circle
![a_c = \frac{v^2}{r} = \frac{30^2}{300} = \frac{900}{300} = 3 m/s^2](https://tex.z-dn.net/?f=a_c%20%3D%20%5Cfrac%7Bv%5E2%7D%7Br%7D%20%3D%20%5Cfrac%7B30%5E2%7D%7B300%7D%20%3D%20%5Cfrac%7B900%7D%7B300%7D%20%3D%203%20m%2Fs%5E2)
So the magnitude of the total acceleration is
![a = \sqrt{a_c^2 + a_l^2} = \sqrt{3^2 + 4^2} = \sqrt{9 + 16} = \sqrt{25} = 5 m/s^2](https://tex.z-dn.net/?f=a%20%3D%20%5Csqrt%7Ba_c%5E2%20%2B%20a_l%5E2%7D%20%3D%20%5Csqrt%7B3%5E2%20%2B%204%5E2%7D%20%3D%20%5Csqrt%7B9%20%2B%2016%7D%20%3D%20%5Csqrt%7B25%7D%20%3D%205%20m%2Fs%5E2)
Answer:
1) No, the car does not travel at constant speed.
2) V = 9 ft/s
3) No, the car does not travel at constant speed.
4) V = 5.9 ft/s
Explanation:
In order to know if the car is traveling at constant speed we need to derive the given formula. That way we get speed as a function of time:
V(t) = 2*t + 2 Since the speed depends on time, the speed is not constant at any time.
For the average speed we evaluate the formula for t=2 and t=5:
d(2) = 8 ft and d(5) = 35 ft
![V_{2-5}=\frac{d(5)-d(2)}{5-2}=9 ft/s](https://tex.z-dn.net/?f=V_%7B2-5%7D%3D%5Cfrac%7Bd%285%29-d%282%29%7D%7B5-2%7D%3D9%20ft%2Fs)
Again, for the average speed we evaluate the formula for t=1.8 and t=2.1:
d(1.8) = 6.84 ft and d(2.1) = 8.61 ft
![V_{1.8-2.1}=\frac{d(2.1)-d(1.8)}{2.1-1.8}=5.9 ft/s](https://tex.z-dn.net/?f=V_%7B1.8-2.1%7D%3D%5Cfrac%7Bd%282.1%29-d%281.8%29%7D%7B2.1-1.8%7D%3D5.9%20ft%2Fs)