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amid [387]
3 years ago
9

How do you change current in a circuit without changing the voltage?

Physics
1 answer:
Sunny_sXe [5.5K]3 years ago
4 0

Decrease the reactance is the correct answer i believe

Explanation:

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HELP PLEASE!!!! 20 POINTS! If we increase the distance traveled over the same period of time, this will (2 points) decrease the
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Increase the speed of it
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3 years ago
A 42.2 kg sled is pulled forward
zaharov [31]

The net force on the sledge  is 31.64N.

Frictional force = µkR

                         = 0.269 x 42.2 x 9.81 = 111.36

net force = 143N - 111.36N

               = 31.64N

refer  brainly.com/question/24557767

#SPJ2

     

7 0
2 years ago
The period and freqency of a wave are inversely related true or false​
Soloha48 [4]

Answer: false

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5 0
3 years ago
Read 2 more answers
A pickup truck and a hatchback car start at the same position. If the truck is moving at a constant 33.2m/s and the hatchback ca
love history [14]

Answer:

The pickup truck and hatchback will meet again at 440.896 m

Explanation:

Let us assume that both vehicles are at origin at the start means initial position is zero i.e. s_{o} = 0. Both the vehicles will cross each other at same time so we will make equations for both and will solve for time.

Truck:

v_{i} = 33.2 m/s, a = 0 (since the velocity is constant), s_{o} = 0

Using s =s_{o}+v_{i}t+1/2at^{2}

s = 33.2t .......... eq (1)

Hatchback:

a=5m/s^{2}, v_{i} = 0 m/s (since initial velocity is zero), s_{o} = 0

Using s =s_{o}+v_{i}t+1/2at^{2}

putting in the data we will get

s=(1/2)(5)t^{2}

now putting 's' value from eq (1)

2.5t^{2}-33.2t=0

which will give,

t = 13.28 s

so both vehicles will meet up gain after 13.28 sec.

putting t = 13.28 in eq (1) will give

s = 440.896 m

So, both vehicles will meet up again at 440.896 m.

7 0
3 years ago
Read 2 more answers
If Shirley pushes one end of a desk to the right with a force of 12.0N and anfernee pushes the desk at the same time to the left
Marianna [84]
The net force does not depend on the mass.

We have 12N to the right, and 19N to the left.
The net force is (19.0-12.0)N=7.0N to the left.

5 0
3 years ago
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