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yan [13]
4 years ago
7

Matter is anything that has

Physics
1 answer:
Svetlanka [38]4 years ago
8 0

Answer:

Space

Explanation:

Hope this helped

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What's the difference between a wavelength and an an amplitude?
valkas [14]
Wavelength - the distance from one wave crest or trough to another wave crest or trough. Amplitude - the distance from the median point or "middle" of the wave straight up to a crest (a maximum) or straight down to a trough (or minimum), which is the peak amplitude; or the distance from a trough straight up to a crest, or a crest straight down to a trough, called peak-to-peak amplitude.
3 0
4 years ago
Read 2 more answers
Tarzan swings on a 31.0 m long vine initially inclined at an angle of 36.0◦ with the vertical. The acceleration of gravity if 9.
Gennadij [26K]

Answer:

v=10.777m/s

Explanation:

Tarzan swing can be thought of as change in potential energy by going from higher location We solve for height of beginning of the swing by using simple cosine equation:

So

31Cos36=25.08\\E_{potential}=mgh\\

ΔE=mg(h₂-h₁)

=m*9.81(31-25.08)\\

The potential energy of Tarzan initial position is converted into kinetic energy of his swing.By using kinetic equation

E_{kinectic}=P_{potential}\\1/2mv^{2}=m*9.81(31.0-25.08)\\(1/2)v^{2}=9.81(31.0-25.08)\\0.5v^{2}=58.07\\v^{2}=58.07/0.5\\v=\sqrt{58.07/0.5}\\ v=10.777m/s    

8 0
3 years ago
What terms are needed to completely describe velocity?
kotegsom [21]
In order to completely describe a velocity,
you need a speed and a direction.
4 0
3 years ago
Andrew skis down a hill.
IceJOKER [234]

Explanation:

gravitational potential energy at the top of the hill, which transforms into kinetic energy as he moves bottom of the hill

that's mean potential energy transfoms into kinetic energy

5 0
3 years ago
The kinetic energy of a moving object is E=12mv2. A 61 kg runner is moving at 10kmh. However, her speedometer is only accurate t
jek_recluse [69]

Answer:

e=3367.2J

%e=1.43%

Explanation:

From the exercise we know two information. The real speed and the experimental measured by the speedometer

v_{r}=10km/h=2.77m/s

Since the speedometer is only accurate to within 0.1km/h the experimental speed is

v_{e}=10km/h-0.1km/h=9.9km/h=2.75m/s

Knowing that we can calculate Kinetic energy for the real and experimental speed

E_{r}=\frac{1}{2}mv^2=\frac{1}{2}(61000g)(2.77m/s)^2=234023J

E_{e}=\frac{1}{2}mv^2=\frac{1}{2}(61000g)(2.75m/s)^2=230656J

Now, the potential error in her calculated kinetic energy is:

e=E_{r}-E_{e}=(234023-230656)J=3367.2J

%e=\frac{E_{r}-E_{e}}{E_{r}}x100=\frac{(234023-230656)J}{234023J}x100=1.43%

4 0
4 years ago
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