Solution :
Speed of the air craft, = 262 m/s
Fuel burns at the rate of, = 3.92 kg/s
Rate at which the engine takes in air, = 85.9 kg/s
Speed of the exhaust gas that are ejected relative to the aircraft, =921 m/s
Therefore, the upward thrust of the jet engine is given by
F = 85.9(921 - 262) + (3.92 x 921)
= 4862635.79 + 3610.32
=
Therefore thrust of the jet engine is .
The speed of the car at the top of the hill is 14m/s
<u>Explanation:</u>
given that
Initial velocity u of the car=0 m/s
The distance can be determined by finding out the difference between the elevation of the first slope and second slope.
elevation of the first slope=26 m
elevation of second slope=16m
distance s=26-16=10 m
acceleration due to gravity g=9.8 m/s2
speed of the car at the top of the hill can be determined by using the equation
speed of the car at the top of the hill is 14m/s