The probability that the spinner lands on an even number or on the unshaded section is; 3/5
<h3>How to find the probability?</h3>
From the spinner attached, we see that the number of sections on the spinner is 5 sections.
Now, we can also see that;
Number of even numbers section = 2
Number of shaded sections = 1
Thus, probability that the spinner lands on an even number or on the unshaded section is;
P(even number or unshaded section) = (2 + 1)/5 = 3/5
Read more about Probability at; brainly.com/question/24756209
#SPJ1
Answer:
in 7hours and 30 mn the cost will be (7.5×d×e) cents
Step-by-step explanation:
To figure out the percentage you got correct, we need to set up fractional proportions.
We already have one fraction, 14/20.
Since we are looking for a percentage, we need to have a maximum total percentage that represents the total score.
100% is the maximum percentage for any total.
So we have our fractional proportions set;
14/20 : x/100
To solve for this, we need to cross multiply the numerator (top number) of one fraction by the denominator (bottom number) of the other fraction.
Let's try this!
14 • 100 = 1400
20 • x = 20x
Now that we have our products, set them as an equation.
20x = 1400.
To solve for x, we need to divide both sides by 20.
20x / 20 = x
1400 / 20 = 70.
You are left with:
x = 70.
Your answer is:
If you get 14/20 on a test, you would get 70% of the questions correct.
I hope this helps!
Answer; 1/4 × 1/6
Step-by-step explanation: To turn a fraction division sentence into a multiplication sentence, simply multiply the second fraction by its reciprocal. For example 1/4 ÷ 6/1 is equaled to 1/4 × 1/6.
I hope this helps! please vote brainliest if so
Answer: Last option.
Step-by-step explanation:
By definition, Inverse variation equations have this form:
Where "k" is the constant of variation.
In this case, it is:
Knowing that 
when 
, we can substitute values into the equation and solve for "k":
Therefore, we can find the value of "n" when 
by substiuting this value and the value of "k" into the equation and solving for "n". Then:
