Answer:
f(t) = 1.22·(173/122)^(t/5)
Step-by-step explanation:
(a) An exponential growth (or decay) function can be written using the form ...
f(t) = (initial value)·(ratio in period)^(t/period)
Here, we're given an initial value of 1.22, a growth ratio of 1.73/1.22 in a period of 5 years, so we can write the function as ...
f(t) = 1.22·(173/122)^(t/5)
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(b) In 2038-2012 = 26 years, the value of the function is ...
f(26) = 1.22·(173/122)^(26/5) ≈ 7.50 . . . . million
Answer: 15
Step-by-step explanation:
x = one point shots
y = two point shots
1) Setup your equations.
x + y = 52
x + 2y = 89
2) Isolate a variable.
x = 52-y
3) Plug in.
(52-y) + 2y = 89
52 +y =89
y=37
4) Solve for x.
x = 52 -37
x=15
5) Check your answer.
15 + 2(37) = 89
15+74=89
89=89
37+15 = 52
52=52
x = one point shots
y = two point shots
1) Setup your equations.
x + y = 52
x + 2y = 89
2) Isolate a variable.
x = 52-y
3) Plug in.
(52-y) + 2y = 89
52 +y =89
y=37
4) Solve for x.
x = 52 -37
x=15
5) Check your answer.
15 + 2(37) = 89
15+74=89
89=89
37+15 = 52
52=52
Answer:
Step-by-step explanation:
7. 
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5. ![\displaystyle 1000[0,85]^8 = 272,490525 ≈ \$272,49](https://tex.z-dn.net/?f=%5Cdisplaystyle%201000%5B0%2C85%5D%5E8%20%3D%20272%2C490525%20%E2%89%88%20%5C%24272%2C49)
4. ![\displaystyle 1000 = a \\ -15\% + 100\% = 1 - r; 85\% = 1 - r \\ 8\:years = time\:[t]](https://tex.z-dn.net/?f=%5Cdisplaystyle%201000%20%3D%20a%20%5C%5C%20-15%5C%25%20%2B%20100%5C%25%20%3D%201%20-%20r%3B%2085%5C%25%20%3D%201%20-%20r%20%5C%5C%208%5C%3Ayears%20%3D%20time%5C%3A%5Bt%5D)
3. ![\displaystyle /text{We need to use the "Exponential Decay" formula} - f(t) = a[1 - r]^t, where a > 0](https://tex.z-dn.net/?f=%5Cdisplaystyle%20%2Ftext%7BWe%20need%20to%20use%20the%20%22Exponential%20Decay%22%20formula%7D%20-%20f%28t%29%20%3D%20a%5B1%20-%20r%5D%5Et%2C%20where%20a%20%3E%200)
2. 
1. 
I am joyous to assist you anytime.
The correct question is
<span>What are the vertex and x-intercepts of the graph of the function given below?
y = x</span>²<span>-2x-35
step 1
convert the equation in the vertex form
y+35=x</span>²-2x
y+35=(x²-2x+1-1)
y+35+1=(x²-2x+1)
y+36=(x-1)²------> equation in the vertex form
the vertex is the point (1,-36)
the answer Part a) is
the vertex is the point (1,-36)
Part b) Find the x-intercepts
we know that
the x-intercepts is when y=0
so
y+36=(x-1)²
for y=0
(x-1)²=36
(+/-)(x-1)=√36-------> (+/-)(x-1)=6
(+)(x-1)=6------> x=6+1-----> x=7
(-)(x-1)=6-----> x=1-6-----> x=-5
the x-intercepts are the points
(7,0) and (-5,0)
the answer part b) is
the x-intercepts are the points (7,0) and (-5,0)
the total answer is the option
<span>A. Vertex: (1, -36); x-intercepts: (7, 0) and (-5, 0)</span>
