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mars1129 [50]
3 years ago
7

Decide whether the pair of lines is parallel, perpendicular, or neither.

Mathematics
1 answer:
maw [93]3 years ago
6 0

The lines are:  B) Perpendicular

Step-by-step explanation:

we have to convert both lines in slope-intercept form to find slopes

So,

3x - 6y = -13\\-6y = -3x-13\\\frac{-6y}{-6} = \frac{-3x-13}{-6}\\\frac{-6y}{-6} = \frac{-3x}{-6}+\frac{-13}{-6}\\y = \frac{1}{2} +\frac{13}{6}

Let m1 be the slope of first line

m_1 = \frac{1}{2}

For the second line:

18x + 9y = 5\\9y = -18x+5\\\frac{9y}{9} = \frac{-18x+5}{9}\\\frac{9y}{9} = \frac{-18}{9}x+\frac{5}{9}\\y = -2x+\frac{5}{9}

Let m2 be the slope of line 2

So,

If the lines are parallel, their slopes are equal

If the lines are perpendicular, product of their slopes is -1

We can see that

\frac{1}{2} * -2 = -1

Hence,

The lines are:  B) Perpendicular

Keywords: Slopes, Parallel lines

Learn more about slopes of lines at:

  • brainly.com/question/4639731
  • brainly.com/question/4655616

#LearnwithBrainly

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