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3 years ago

Decide whether the pair of lines is parallel, perpendicular, or neither.

Mathematics

1 answer:

maw [93]3 years ago

6 0

The lines are: B) Perpendicular

Step-by-step explanation:

we have to convert both lines in slope-intercept form to find slopes

So,

$3x - 6y = -13\\-6y = -3x-13\\\frac{-6y}{-6} = \frac{-3x-13}{-6}\\\frac{-6y}{-6} = \frac{-3x}{-6}+\frac{-13}{-6}\\y = \frac{1}{2} +\frac{13}{6}$

Let m1 be the slope of first line

$m_1 = \frac{1}{2}$

For the second line:

$18x + 9y = 5\\9y = -18x+5\\\frac{9y}{9} = \frac{-18x+5}{9}\\\frac{9y}{9} = \frac{-18}{9}x+\frac{5}{9}\\y = -2x+\frac{5}{9}$

Let m2 be the slope of line 2

So,

If the lines are parallel, their slopes are equal

If the lines are perpendicular, product of their slopes is -1

We can see that

$\frac{1}{2} * -2 = -1$

Hence,

The lines are: B) Perpendicular

Keywords: Slopes, Parallel lines

Learn more about slopes of lines at:

#LearnwithBrainly

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