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chubhunter [2.5K]
3 years ago
15

The reaction of HCl with NaOH is represented by the equation HCl( aq) + NaOH( aq) ® NaCl( aq) + H 2O( l) What volume of 0.631 M

HCl is required to titrate 15.8 mL of 0.321 M NaOH?
Chemistry
1 answer:
Darina [25.2K]3 years ago
5 0

8.04 mL.

<h3>Explanation</h3>

How many moles of NaOH?

Note the unit:

V = 15.8 \; \textbf{mL} = \dfrac{15.8}{1000}\;\textbf{L} = 0.0158 \; \text{L}.

n = c\cdot V = 0.0158 \times0.321 = 0.00507\;\text{mol}.

How many moles of HCl?

As seen in the equation, HCl and NaOH reacts at a 1:1 ratio.

n(\text{HCl}) = n(\text{NaOH}) = 0.00507\;\text{mol}.

How many mL of HCl?

V = \dfrac{n}{c} =\dfrac{0.00507}{0.631} = 0.00804\;\text{L} = 0.00804\times 1000 \;\textbf{mL} = 8.04\;\text{mL}.

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If 18.7ml of 0.01500M aqueous HCl is required to titrâtes 15.00ml of an aqueous solution of NaOH to the equivalence point, what
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Explanation:

Step 1: Write the balanced neutralization reaction

NaOH + HCl ⇒ NaCl + H₂O

Step 2: Calculate the reacting moles of HCl

18.7 mL of 0.01500 M HCl react.

0.0187 L × 0.01500 mol/L = 2.81 × 10⁻⁴ mol

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