Consider the following reaction. Upper C upper O subscript 2 (g) plus upper H subscript 2 (g) right arrow Upper C upper O (g) pl
2 answers:
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Answer:
The right solution is "".
Explanation:
As we know,
1 mole electron =
Total energy =
=
For single electron,
The amount of energy will be:
=
=
Answer:
The standard enthalpy of formation of methanol is, -238.7 kJ/mole
Explanation:
The formation reaction of CH_3OH will be,
The intermediate balanced chemical reaction will be,
..[1]
..[2]
..[3]
Now we will reverse the reaction 3, multiply reaction 2 by 2 then adding all the equations, Using Hess's law:
We get :
..[1]
..[2]
[3]
The expression for enthalpy of formation of will be,
The standard enthalpy of formation of methanol is, -238.7 kJ/mole