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zhannawk [14.2K]
3 years ago
11

A student determined that the weight-percent recovery for his isolated caffeine proved to be 1.5%. The student was concerned, ex

pecting a yield of at least 50% as in many of the previous experiments. Was his concern legitimate? Explain.
Chemistry
1 answer:
Salsk061 [2.6K]3 years ago
6 0

Yes. Percent yield shows how efficient one's method is. If his isolated caffeine proved to be at only 1.5%, compared to least 50% as in many of the previous experiments, the student should be very concerned as it shows that something caused the yield to sharply drop.

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An indicator was used to test a water solution with a pH of 12. Which indicator color would be observed?
juin [17]

Answer:

4) pink  phenolphthalein

Explanation:

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Water interacts with polar substances like –OH groups but not with non-polar substances like methyl (-CH3) or ethyl groups (-CH2
Otrada [13]
To answer this, we look at the polarities of these molecules given. A molecule is said to be polar when there is an unequal shraing of electrons the opposite is called nonpolar.
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<span>CH3 CH2 CH2 CH2 CH2 CH3 = nonpolar</span>
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3 years ago
Give the name and formula for the acid derived from each of the following anions: (a) perchlorate (b) N03- (c) bromite (d) H2PO4
Vlada [557]

Answer:

(a) Perchloric acid (HClO₄)

(b) Nitric acid (HNO₃)

(c) Bromous acid (HBrO₂)

(d) Phosphoric Acid (H₃PO₄)

Explanation:

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Thus,

(a) Perchlorate (ClO₄⁻) ion:

The acid that furnish perchlorate ion is <u>perchloric acid (HClO₄)</u>.

(b)  NO₃⁻ ion:

The acid that furnish NO₃⁻ ions is <u>Nitric acid (HNO₃)</u>.

(c) bromite (BrO₂⁻) ion:

The acid that furnish BrO₂⁻ ions is <u>Bromous acid (HBrO₂)</u>.

(d)  H₂PO₄⁻ ion:

The acid that furnish H₂PO₄⁻ ions is <u>Phosphoric Acid (H₃PO₄)</u>.

6 0
3 years ago
The natural gas in a storage reservoir, under a pressure of 1.00 atmosphere, has a volume of 2.74 × 109 L at 20.0°C. The tempera
Soloha48 [4]

Answer : The final volume of gas will be, 2.36\times 10^9L

Explanation :

Charles' Law : It is defined as the volume of gas is directly proportional to the temperature of the gas at constant pressure and number of moles.

V\propto T

or,

\frac{V_1}{V_2}=\frac{T_1}{T_2}

where,

V_1 = initial volume of gas = 2.74\times 10^9L

V_2 = final volume of gas = ?

T_1 = initial temperature of gas = 20.0^oC=273+20.0=293K

T_2 = final temperature of gas = -20.0^oC=273+(-20.0)=253K

Now put all the given values in the above formula, we get the final volume of the gas.

\frac{2.74\times 10^9L}{V_2}=\frac{293K}{253K}

V_2=2.36\times 10^9L

Therefore, the final volume of gas will be, 2.36\times 10^9L

8 0
3 years ago
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The electrical forces between the particles would decrease -q-q.

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