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Veronika [31]
2 years ago
7

What is the main reason that it takes 2 to 3 minutes for the reaction to occur between sucrose and sulfuric acid in the dehydrat

ion of sucrose?
Chemistry
2 answers:
soldier1979 [14.2K]2 years ago
5 0

 There is a time delay of almost two to three minutes before the reaction proceeds because of the following processes:

<span>1)    </span><span> The acid starts to go yellow as the dehydration begins.</span>

<span>2)    </span><span> The rate of dehydration then accelerates as the acid heats up because the reaction is exothermic/chemical (releases energy by light or heat).  As the sugar molecules are stripped of water, the heat generated turns the water into steam which then expands the remaining carbon into a porous, smoking, black column.</span>

<span>3)    </span>This expands out of the reaction vessel, producing a choking acrid vapor and the smell of burned sugar.

<span> At this stage, sulfuric acid is highly corrosive and will burn skin so one must avoid contact with it. </span>

BARSIC [14]2 years ago
4 0
The are different reasons and these are the following:
1) The acid starts to go yellow as the dehydration begins.
2)The rate of dehydration then accelerates as the acid heats up .
3)This expands out of the reaction vessel.
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How many moles are in 24.75 g of H2O? What is given the conversation and the unknown?
riadik2000 [5.3K]

Answer:

1.373 mol H₂O

General Formulas and Concepts:

<u>Chemistry - Atomic Structure</u>

  • Reading a Periodic Table
  • Using Dimensional Analysis

Explanation:

<u>Step 1: Define</u>

24.75 g H₂O

<u>Step 2: Identify Conversions</u>

Molar Mass of H - 1.01 g/mol

Molar Mass of O - 16.00 g/mol

Molar Mass of H₂O - 2(1.01) + 16.00 = 18.02 g/mol

<u>Step 3: Convert</u>

<u />24.75 \ g \ H_2O(\frac{1 \ mol \ H_2O}{18.02 \ g \ H_2O} ) = 1.37347 mol H₂O

<u>Step 4: Check</u>

<em>We are given 4 sig figs. Follow sig fig rules and round.</em>

1.37347 mol H₂O ≈ 1.373 mol H₂O

7 0
2 years ago
Find the molar mass of this
kirill115 [55]

Explanation:

Given problem:

Find the molar mass of:

  SO₃ and C₁₀H₈

Solution:

The molar mass of a compound is the mass in grams of one mole of the substance.

To solve this, we are going to add the individual atomic masses of the elements in the compound;

  Atomic mass;

       S = 32g/mol; O = 16g/mol; C = 12g/mol and H = 1g/mol

For  SO₃;

     = 32 + 3(16)

     = 32 + 48

     = 80g/mol

For C₁₀H₈

      = 10(12) + 8(1)

      = 120 + 8

       = 128g/mol

7 0
2 years ago
How is it determined the highest energy level an atom has
BaLLatris [955]

Answer:

C. Atomic mass

Explanation:

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2 years ago
Isotopes that decay with a nuclear break-up and emit a significant amount of energy are said to be ________.
podryga [215]

Answer to this is Radioactive isotopes.

Isotopes are the species of the same element having different atomic masses that means the number of protons remains the same but number of neutrons do differ. For example _{1}^{2}\textrm{H} and _{1}^{3}\textrm{H} are the two isotopes of Hydrogen (_{1}^{1}\textrm{H} ).

Radioactive isotopes are the isotopes which release some kind of energy in the form of alpha particles, beta particles or gamma radiation. Examples of each of the decay processes are :

Alpha Decay: In this decay one alpha particle having atomic mass 4 and atomic number 2 or we can say a He molecule will come out. _{Z}^{A}\textrm{X}\rightarrow _{Z-2}^{A-4}\textrm{Y}+_{2}^{4}\alpha

Beta Decay: In this decay a \beta particle is emitted increasing the atomic number of the reactant by 1 unit.

_{Z}^{A}\textrm{X}\rightarrow _{Z+1}^{A}\textrm{Y}+_{-1}^{0}\beta

Gamma Radiation: In this type of reaction only radiation is emitted out which does not change the original molecule.

_{Z}^{A}\textrm{X}\rightarrow _{Z}^{A}\textrm{X}+\gamma\text{ radiation}

3 0
2 years ago
A sample of gas at 1.10 atm has a volume of 326 mL. What is the new volume if the pressure is changed to 1.90 atm?
Brut [27]

Answer

For this we use ideal gas equation which is:

P1V1 = P2V2

P1 = 1.10 atm

V1 = 326 ml

P2 = 1.90

V2 = ?

By rearranging the ideal gas equation:

V2 =  P1V1 ÷ P2

V2 = 1.10 × 326 ÷1.90

V2 = 358.6 ÷ 1.90

V2 = 188.7 ml

8 0
3 years ago
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