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gizmo_the_mogwai [7]
4 years ago
8

What’s a example of a compound

Chemistry
2 answers:
defon4 years ago
8 0

Answer: Water. H2O

Explanation: a chemical compound is composed of many identical molecules made from more than one element, in this case Hydrogen and Oxygen.

kykrilka [37]4 years ago
7 0

Answer:

Water, carbon dioxide

Explanation

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The answer is water is a liquid
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Does any one have a sixth grade Ohio science fusion book
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Nope, sure don't sesrch it on amazon or something. Maybe youll find one and be able to but it.
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How many moles of solute particles are present in 1 mL of each of the following aqueous solutions?
olga_2 [115]

A mole is a very important unit of measurement that chemists use. A mole of something means you have 602,214,076,000,000,000,000,000 of that thing, like how having a dozen eggs means you have twelve eggs. Chemists have to measure using moles for very small things like atoms, molecules, or other particles.

<h3>What is mole and atoms?</h3>

The number of atoms or other particles in a mole is the same for all substances. The mole is related to the mass of an element in the following way: one mole of carbon-12 atoms has 6.02214076 × 1023 atoms and a mass of 12 grams.

<h3>Why is the mole unit so important?</h3>

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7 0
2 years ago
How many unpaired electrons would you expect for the complex ion: [fe(nh3)6]2+?
GarryVolchara [31]
The N from NH3 forms a coordinate covalent bond with the metal iron as in this case. The iron itself is at the "center" of the ligate complex ion. Since the net ionic charge is at 2+, it can be said that there is one pair of unpaired electrons for <span>[fe(nh3)6]2+.</span>
4 0
3 years ago
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Which reactant is limiting?<br><br><br>Show work
fenix001 [56]

Answer:

  • 1. Iodine is the limiting reactant

  • 2. 6molAlI_3

Explanation:

<u>1. Balanced chemcial equation:</u>

      2Al+3I_2\rightarrow 2AlI_3

<u>2. Theoretical mole ratio</u>

It is the ratio of the coefficients of the reactants in the balanced chemical equation:

           \dfrac{2molAl}{3molI_2}

<u>3. Actual ratio</u>

<u />

It is ratio of the moles available to reat:

       \dfrac{9molAl}{9molI_2}

<u>4. Comparison</u>

            \dfrac{9molAl}{9molI_2}>\dfrac{2molAl}{3molI_2}

Then, there are more aluminum available than what is needed to react with the 9 moles of iodine, meaning that the aluminum is in excess and the iodine will react completely, being the latter the limiting reactant.

Conclusion: iodine is the limiting reactant.

<u>5. How much aluminum iodide will be produced?</u>

Use the theoretical mole ratio of aluminum iodide to iodide:

       \dfrac{2molAlI_3}{3molI_2}\times 9molI_2=6molAlI_3\leftarrow answer

5 0
3 years ago
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