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Lelechka [254]
4 years ago
5

The density of copper is 8.92 g/mL. The mass of a piece of copper that has a volume of 10.3 mL is

Chemistry
1 answer:
m_a_m_a [10]4 years ago
8 0

Answer:

The answer is

<h2>91.9 g</h2>

Explanation:

The mass of a substance when given the density and volume can be found by using the formula

<h3>mass = Density × volume</h3>

From the question

volume of copper = 10.3 mL

density = 8.92 g/mL

The mass is

mass = 8.92 × 10.3 = 91.876

We have the final answer as

<h3>91.9 g</h3>

Hope this helps you

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The Paleozoic does NOT include this period: _____.
Gwar [14]

Answer:

Jurassic

Explanation:

There are six periods in the Paleozoic Era: Cambrian, Ordovician, Silurian, Devonian, Carboniferous (alternatively subdivided into the Mississippian Period and the Pennsylvanian Period), and the Permian

3 0
3 years ago
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10. Differentiate between Halogens and Noble Gases.
Digiron [165]

Answer: Halogens are very reactive because they need one electron to gain a full set of valence electrons whereas noble gases already have this one electron and are extremely unstable since they have their full octet. (8 electron set) They tend to not form chemical bonds because of this.

3 0
3 years ago
A mixture of 60 mol % n-propylcyclohexane and 40 mol % n-propylbenzene is distilled through a simple distillation apparatus; ass
Dvinal [7]

Answer:

61 mole % propylcyclohexane and 39 mole % propylbenzene

Explanation:

For convenience, let’s call propylcyclohexane <em>Component 1 </em>and propylbenzene <em>Component 2</em>.

According to <em>Raoult’s Law</em>,  

p_{1} = \chi_{1}p_{1}^{\circ} and

p_{2} = \chi_{2}p_{2}^{\circ}

where

<em>p</em>₁ and <em>p</em>₂ are the vapour pressures of the components above the solution

χ₁ and χ₂ are the mole \fractions of the components

<em>p</em>₁° and <em>p</em>₂° are the vapour pressures of the pure components.

So,  

p_{1} = 0.60 \times \text{769 torr} = \text{ 461 torr}

p_{2} = 0.40 \times \text{725 torr} = \text{ 290 torr}

p_{\text{tot}} = <em>p</em>₁ + <em>p</em>₂= 461 torr + 290 torr = 751 torr

∴ In the vapour

\chi_{1} = \frac{p_{1}}{p_{\text{tot}} } = \frac{\text{461 torr} }{\text{751 torr}} = 0.61

χ₂ = 1 – χ₁ = 1 - 0.61 = 0.39

8 0
3 years ago
What volume will 20.0g of Argon occupy at STP?
Yuki888 [10]
Molar mass Argon = 39.948 g/mol

1 mol ------ 39.948 g
  mol ----- 20.0 g 

mol = 20.0 * 1 / 39.948

= 0.5006 moles

1 mol --------------------- 22.4 L ( at STP )
0.5006 moles ------------- L 

L = 0.5006 * 22.4

= 11.21 L

hope this helps!
6 0
3 years ago
Aqueous hydrochloric acid reacts with solid sodium hydroxide to produce aqueous sodium chloride and liquid water. What is the th
AVprozaik [17]

Answer:

5.28g

Explanation:

The equation for the reaction between is given below:

HCl + NaOH —> NaCl + H2O

Let us determine which will be the limiting reactant.

Molar Mass of HCl = 1 + 35.5 = 36.5g/mol

Mass of HCl = 3.3g

Number of mole = Mass /Molar Mass

Number of mole of HCl = 3.3/36.5 = 0.09mole

Molar Mass of NaOH = 23 + 16 + 1 = 40g/mol

Mass of NaOH = 4.6g

Number of mole = Mass /Molar Mass

Number of mole of NaOH = 4.6/40 = 0.115mole

From the equation,

1mole of HCl required 1mole of NaOH.

Therefore, 0.09mole of HCl will also require 0.09mole of NaOH.

Now, we see that NaOH is excess and HCl is limiting.

Now we can calculate the theoretical yield as follows:

Molar Mass of NaCl = 23 + 35.5 = 58.5g/mol

From the equation,

36.5g of HCl produced 58.5g of NaCl.

Therefore, 3.3g of HCl will produce = (3.3 x 58.5)/36.5 = 5.28g

Therefore, the theoretical yield of NaCl is 5.28g

5 0
3 years ago
Read 2 more answers
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