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Lelechka [254]
4 years ago
5

The density of copper is 8.92 g/mL. The mass of a piece of copper that has a volume of 10.3 mL is

Chemistry
1 answer:
m_a_m_a [10]4 years ago
8 0

Answer:

The answer is

<h2>91.9 g</h2>

Explanation:

The mass of a substance when given the density and volume can be found by using the formula

<h3>mass = Density × volume</h3>

From the question

volume of copper = 10.3 mL

density = 8.92 g/mL

The mass is

mass = 8.92 × 10.3 = 91.876

We have the final answer as

<h3>91.9 g</h3>

Hope this helps you

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Provide the mass number of Fe, which has 29 neutrons
zmey [24]

Answer:

55.845 u

Explanation:

Fe, iron, has 29 neutrons and a atomic mass of 55.845 u

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3 years ago
Many metals react with acids to produce hydrogen gas. A certain reaction produces 32.6 L of hydrogen gas at STP. How many moles
morpeh [17]

Answer: 1.46moles

Explanation:

Applying PV= nRT

P= 1atm, V= 32.6L, R= 0.082, T = 273K

Substitute and simplify

1×32.6/(0.082×273)=n

n= 1.46moles

4 0
3 years ago
What is the mass, in grams, 6.5 mol of sodium nitrate (nano3)? please show all work?
ladessa [460]
Mass is the property of a physical body and the resistance to acceleration when a net force is applied on the body.  
The atomic mass of sodium (Na) is = 22.98 
The atomic mass of nitrate (N) is = 14.00 
The atomic mass of oxygen (O) is = 15.99  
The sodium nitrate (NaNO3) consists of the atomic masses of Na+N+(O)3 = 85 grams  
Therefore, the mass of 6.5 mol of sodium nitrate is = 6.5 * 1 mol of NaNO3 
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6 0
3 years ago
Read 2 more answers
A distance of one centimeter is the same as ?
rodikova [14]
C because its meters right
4 0
4 years ago
A material has an ASTM grain size number of 7. Determine the magnification, if the number of grains per square inch observed is:
Luden [163]

Answer:

A) M = 100X

B) M = 36X

C) M = 178.88X

Explanation:

Given data:

ASTM grain size number 7

a) total grain per inch^2 - 64 grain/inch^2

we know that number of grain per square inch is given as

Nm = 2^{n-1} (\frac{100}{M})^2

where M is magnification, n is grain size

therefore we have

64 = 2^{7-1}(\frac{100}{M})^2

solving for M we get

M = 100 X

B)  total grain per inch^2 = 500 grain/inch^2

we know that number of grain per square inch is given as

Nm = 2^{n-1} (\frac{100}{M})^2

where M is magnification, n is grain size

therefore we have500 = 2^{7-1}(\frac{100}{M})^2

solving for M we get

M = 36 X

C) Total grain per inch^2 = 20 grain/inch^2

we know that number of grain per square inch is given as

Nm = 2^{n-1} (\frac{100}{M})^2

where M is magnification, n is grain size

therefore we have20 = 2^{7-1}(\frac{100}{M})^2

solving for M we get

M = 178.88 X

8 0
3 years ago
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