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iragen [17]
3 years ago
10

Find a point on the y-axis that is equidistant from the points (7, −7) and (1, 1).

Mathematics
1 answer:
jeka57 [31]3 years ago
6 0
Hello : 
<span>a point on the y-axis is : P( 0, y)
</span>PA = PB  or  PA² = PB².... A(7, -7)    B(1,1)
(7-0)²+(-7-y)² = (1-0)² + (1-y)²
49+49+14y+y² = 1+1-2y+y²
16y = - 96
y= - 6 
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When graphing do you use an open or closed circle for &gt;
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open

Step-by-step explanation:

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3 years ago
One angle of a right triangle measures 70 degrees. What is the other acute angle?
Sunny_sXe [5.5K]

Answer:

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Step-by-step explanation:

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4 0
3 years ago
Use point-slope form − 1 = ( − 1) to find the equation of the line that passes through the point (−3,5) and has slope = −2 . Wri
Tom [10]

Answer:

y - 5 = -2(x + 3)

Step-by-step explanation:

When you write an equation in point-slope form, you only need two things: a point and a slope.

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slope (m): -2

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y - y₁ = m(x - x₁)

Plug in what you know.

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This is your equation.

Learn with another example:

brainly.com/question/24436844

8 0
2 years ago
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7 0
3 years ago
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miss Akunina [59]

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Step-by-step explanation:

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= log (x^6*x^7)

= log x^13.

8 0
3 years ago
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