3 years ago

Find a point on the y-axis that is equidistant from the points (7, −7) and (1, 1).

1 answer:

6 0

Hello :
<span>a point on the y-axis is : P( 0, y)
</span>PA = PB or PA² = PB².... A(7, -7) B(1,1)
(7-0)²+(-7-y)² = (1-0)² + (1-y)²
49+49+14y+y² = 1+1-2y+y²
16y = - 96
y= - 6

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Step-by-step explanation:

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