Answer:
Step-by-step explanation:
x-4=0
x=4
p(x)=cx^3-15x-68=0
p(x)=c(4)^3-15(4)-68=0
p(x)=64c-60+68=0
p(x)=64c+8=0
p(x)=64c=-8
p(x)=c=-8/64
p(x)=c=-1/8
Answer:
Step-by-step explanation:
We are to show that 
<u>Proof:</u>
From trigonometry identity;
From trigonometry, 2sinAcosA = Sin2A
Also note that sin(B-C) = sinBcosC - cosBsinC
sin420cos140 - cos420sin140 = sin(420-140)
The resulting equation becomes;
= 
Answer: g(h(3)) = 59
Step-by-step explanation:
Well if its x^3 I assume it is because you wrote other coefficients before the variable.
2(3) - 2 = 6-2 = 4
So 4 is the x input for h(x)
4^3 -5 = 64-5 = 59
Answer: Your answer is the third one, a function assigns to each input exactly one output.
If you have a true function, there will only be one output for each input, if you had more than one, it isn't a function.
You add two equations together to eliminate a variable. This particular problem is nice, because it's already setup to eliminate X.
3x - 4y = 9
<span>-3x + 2y = 9
</span>
When we add these two together, 3x - 3x cancels each other out, leaving us with 0x, or nothing.
We continue with -4y + 2y (leaves us with -2y) and 9+9 (18).
-2y = 18
18/-2 = -9.
Now we have y = -9, and we can go back into the problems to solve for x.
<span>3x - 4(-9) = 9
</span>
3x + 36 = 9.
3x = -27
x = -9.
Confirm with the final equation:
-3(-9) + 2(-9) = 9
27 - 18 = 9
9 = 9 --- Confirmed.
