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Irina18 [472]
3 years ago
5

HURRY PLZ IM ON A TIME LIMIT!!!!

Mathematics
1 answer:
Nana76 [90]3 years ago
8 0

Answer:

23°

Step-by-step explanation:

If you have any questions about the way I solved it, don't hesitate to ask me in the comments below ;)

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Hey:) can you please help me posted picture of question
mr Goodwill [35]
The top row contains the product of x^{2} with each term of the expressions x^{6}+ x^{4}+ x^{2} and bottom row contains the product of -1 with each term of expression x^{6}+ x^{4}+ x^{2} .

The final result will be the sum of terms of both rows as shown below:

( x^{6}+ x^{4} + x^{2} )( x^{2} -1) \\  \\ 
= x^{2} ( x^{6}+ x^{4} + x^{2} )-1( x^{6}+ x^{4} + x^{2} ) \\  \\ 
= x^{8}+ x^{6}+ x^{4}- x^{6}- x^{4}- x^{2}  \\  \\ 
= x^{8}- x^{2}

So the correct answer is option D
8 0
3 years ago
show that thw roots of the equation (x-a)(x_b)=k^2 are always real if a,b and k are real. Please I really need help with this
VLD [36.1K]

Answer:

see explanation

Step-by-step explanation:

Check the value of the discriminant

Δ = b² - 4ac

• If b² - 4ac > 0 then roots are real

• If b² - 4ac = 0 roots are real and equal

• If b² - 4ac < 0 then roots are not real

given (x - a)(x - b) = k² ( expand factors )

x² - bx - ax - k² = 0 ( in standard form )

x² + x(- a - b) - k² = 0

with a = 1, b = (- a - b), c = -k²

b² - 4ac = (- a - b)² + 4k²

For a, b, k ∈ R then (- a - b)² ≥ 0 and 4k² ≥ 0

Hence roots of the equation are always real for a, b, k ∈ R


           

8 0
3 years ago
Gabriella swims 2 laps per minute. What is the rate unit?
My name is Ann [436]

Answer:

1/2

Step-by-step explanation:

THIS IS THE CORRECT ANSWER DONT DELETE

8 0
3 years ago
Read 2 more answers
Hellppppppp with this twoooooooo
liberstina [14]
15.

0.20*x = 0.01*x + 38 => 0.19*x = 38 =>( 19/100 )*x = 38 => x = 3800/19 => x = 200.
6 0
3 years ago
What is the area of the figure graphed below?
Vedmedyk [2.9K]
A i think sorry if i’m wrong
5 0
3 years ago
Read 2 more answers
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