<h3>Answer</h3>
Heat : 12 kJ, to maintain hydrogen bonds
<h3>Further explanation</h3>
Given
A 2.00mole sample ⇒ n = 2 mol
H₂O(s) at 0°C melted, producing H₂O(l) at 0°C
Required
the amount of heat required
the changes that took place
Analysis
Conversion of mol to mass
Use formula of Heat :
Q = mLf (melting/freezing)
Lf=latent heat of fusion (for water=334 J/g)
Solution
mass H₂O(MW=18 g/mol) :
Heat required :
The absorbed heat is used to maintain hydrogen bonds in water molecules (there are two hydrogen bonds per molecule)
Paraphrase
The amount of heat required : 12 kJ, and to maintain hydrogen bonds
Answer: Tetonic plates
Explanation: just because
Answer:
3.68 L
Explanation:
- Use combined gas law
- Change C to K
- Hope that helped! If you want to learn how to do these, I would be glad to help.
B. the shape of a molecule determines its properties and interactions
Answer:
62.9%
Explanation:
Step 1: Given data
- Mass of hydrate sodium carbonate (mNa₂CO₃.xH₂O): 71.5 g
- Mass of anhydrous sodium carbonate (mNa₂CO₃): 26.5 g
Step 2: Calculate the mass lost of water
We will use the following expression.
mH₂O = mNa₂CO₃.xH₂O - mNa₂CO₃
mH₂O = 71.5 g - 26.5 g = 45.0 g
Step 3: Calculate the percent of water in the hydrate sodium carbonate
We will use the following expression.
%H₂O = mH₂O / mNa₂CO₃.xH₂O × 100%
%H₂O = 45.0 g / 71.5 g × 100%
%H₂O = 62.9%