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ololo11 [35]
3 years ago
6

How do you do Number 4​

Chemistry
1 answer:
tiny-mole [99]3 years ago
8 0

Answer:

.4401

Explanation:

bc the formula for the mass is density × volume

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How many grams of dry nh4cl need to be added to 2.50 l of a 0.800 m solution of ammonia, nh3, to prepare a buffer solution that
tia_tia [17]

Answer:

The correct answer is 574.59 grams.

Explanation:

Based on the given information, the number of moles of NH₃ will be,  

= 2.50 L × 0.800 mol/L

= 2 mol

The given pH of a buffer is 8.53

pH + pOH = 14.00

pOH = 14.00 - pH

pOH = 14.00 - 8.53

pOH = 5.47

The Kb of ammonia given is 1.8 * 10^-5. Now pKb = -logKb,  

= -log (1.8 ×10⁻⁵)

= 5.00 - log 1.8

= 5.00 - 0.26

= 4.74

Based on Henderson equation:  

pOH = pKb + log ([salt]/[base])

pOH = pKb + [NH₄⁺]/[NH₃]

5.47 = 4.74 + log ([NH₄⁺]/[NH₃])

log([NH₄⁺]/[NH₃]) = 5.47-4.74 = 0.73

[NH₄⁺]/[NH₃] = 10^0.73= 5.37

[NH₄⁺ = 5.37 × 2 mol = 10.74 mol

Now the mass of dry ammonium chloride required is,  

mass of NH₄Cl = 10.74 mol × 53.5 g/mol

= 574.59 grams.  

8 0
3 years ago
using the structure of the molecule and the IUPAC nomenclature rules, predict the name of the ternary molecule HCN A) hydrocyani
Alexus [3.1K]
Answer is: hydrogen cyanide (formonitrile).
Anion CN⁻ is cyanide. Cyanide <span>consists of a </span>carbon<span> atom </span>triple bonded<span> to a </span>nitrogen atom (<span>C≡N).</span>
Hydrogen cyanide is  colorless, poisonous liquid, <span>also weakly </span>acidic.  Salts<span> of the cyanide anion are called cyanides.</span>
6 0
3 years ago
Karen and nbsp; measures the initial volume of water as 12.5ml and nbsp; she then adds a 2.3 gram rubber stopper and the volume
Ivenika [448]

Answer:

8.3mL

Explanation:

According to the question, the initial volume of a measured amount of water is 12.5mL. Karen then adds a rubber stopper that weighs 2.3grams. This increases the volume of the water.

The increase in the volume of the water is attributed to the rubber stopper. Hence, to calculate the volume of the rubber stopper, we subtract the initial volume of the water from the final volume. i.e.

Volume of added rubber stopper = final volume of water - initial volume of water

= 20.8 - 12.5

= 8.3mL

Hence, the volume of the rubber stopper is 8.3mL

8 0
4 years ago
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