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Lelu [443]
3 years ago
6

Which is the formula mass of Na₂SO₄? * 1. 119 amu 2. 125 amu 3. 142 amu 4. 174 amu

Chemistry
2 answers:
ANTONII [103]3 years ago
4 0

Answer:

the answer is option 3.

Ad libitum [116K]3 years ago
3 0
3 is the right answer
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Define motion of particles in matter
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Answer:

Explanation:

The states that all of the particles that make up matter are constantly in motion. As a result, all particles in matter have kinetic energy. The kinetic theory of matter helps explain the different states of matter—solid, liquid, and gas. ... Particles do not always move at the same speed.

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A gas is collected over water at a certain temperature. The total pressure is 762. mmHg. The vapor pressure of water at this tem
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I Believe The Answer Is D.

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The attractions that allow molecules of krypton to exist in the solid phase are due to:
OLga [1]

Answer:

4) Van der waals forces

Explanation:

Krypton (Kr) belongs to the noble gas group and has fully filled valence orbitals. In the solid phase, Kr exists as a white solid with a face centered cubic structure.

Intermolecular forces of attraction from the strongest to the weakest include:

Ionic > hydrogen bonding > dipole-dipole > london dispersion

Kr is monoatomic and non-polar. When fully filled (stable) valence orbitals of 2 Kr atoms approach each other in close proximity they experience a repulsive force which prevents the formation of strong bonds. Thus, the only force of attraction in Kr is the long range weak Van Der Waals force also known as the london dispersion force.

7 0
3 years ago
A lead mass is heated and placed in a foam cup calorimeter containing 40.0 mL of water at 17.0°C. The water reaches a temperatur
lbvjy [14]

Answer: 502 Joules

Explanation:

To calculate the mass of water, we use the equation:

\text{Density of substance}=\frac{\text{Mass of substance}}{\text{Volume of substance}}

Density of water = 1 g/mL

Volume of water = 40.0 mL

Putting values in above equation, we get:

1g/mL=\frac{\text{Mass of water}}{40.0mL}\\\\\text{Mass of water}=(1g/mL\times 40.0mL)=40.0g

When metal is dipped in water, the amount of heat released by lead will be equal to the amount of heat absorbed by water.

Heat_{\text{absorbed}}=Heat_{\text{released}}

The equation used to calculate heat released or absorbed follows:

q=m\times c\times \Delta T

q = heat absorbed by water

m = mass of water = 40.0 g

T_{final} = final temperature of water = 20.0°C

T_{initial = initial temperature of water = 17.0°C

c = specific heat of water= 4.186 J/g°C

Putting values in equation 1, we get:

q=40.0\times 4.186\times (20.0-17.0)]

q=502J

Hence, the joules of heat were re-leased by the lead is 502

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3 years ago
Where is the carbon in a temperate
tangare [24]

In the high temperate

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