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2 years ago

Iron reacts slowly with oxygen and water to form a compound commonly called rust (Fe₂O₃?4H₂O). For 45.2 kg of rust, calculate

1 answer:

4 0

Rust (Fe2O3. 4H2O) is formed when iron interacts slowly with oxygen and water. Mass of Fe in grams is 2.18 x 10⁴ g.

<h3>What is the explanation?</h3>

There are 2 moles of Fe atoms in 1 mole of Fe2O3-4H2O. The number of moles of Fe atoms in 45.2 kg rust is shown below.

Moles of Fe = 195.01 mol Fe₂O₃.4H₂O ( $\frac{2 mol Fe }{1 mol Fe₂O₃.4H₂O}$ )

Moles of Fe = 390.02 mol Fe

Multiply the calculated number of moles of iron, Fe, by its molar mass which is 55.85 $\frac{g}{mol}$

Mass of Fe = 390.02 mol Fe ( $\frac{55.85 g Fe}{mol Fe}$ )

Mass of Fe = 2.18 x 10⁴ g Fe

Avogadro's number (6.022 x 1023) of molecules (or formula units) make up one mole of a substance (ionic compound). The mass of 1 mole of a chemical is indicated by its molar mass. It provides you with the amount of grams per mole of a substance, to put it another way.

To learn more about moles visit:

brainly.com/question/26416088

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<h3>Mole calculation</h3>

To calculate the molar mass of a compound it is necessary to have knowledge of the atomic mass of all the elements involved.

In the case of the question, we have the reaction between flourine and magnesium, which represents the element of group 2 with the presented electronic configuration.

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