Question

Iron reacts slowly with oxygen and water to form a compound commonly called rust (Fe₂O₃?4H₂O). For 45.2 kg of rust, calculate

Answer 1

Rust (Fe2O3. 4H2O) is formed when iron interacts slowly with oxygen and water. Mass of Fe in grams is 2.18 x 10⁴ g.

What is the explanation?

There are 2 moles of Fe atoms in 1 mole of Fe2O3-4H2O. The number of moles of Fe atoms in 45.2 kg rust is shown below.

Moles of Fe = 195.01 mol Fe₂O₃.4H₂O ( $\frac{2 mol Fe }{1 mol Fe₂O₃.4H₂O}$ )

Moles of Fe = 390.02 mol Fe

Multiply the calculated number of moles of iron, Fe, by its molar mass which is 55.85 $\frac{g}{mol}$

Mass of Fe = 390.02 mol Fe ( $\frac{55.85 g Fe}{mol Fe}$ )

Mass of Fe = 2.18 x 10⁴ g Fe

Avogadro's number (6.022 x 1023) of molecules (or formula units) make up one mole of a substance (ionic compound). The mass of 1 mole of a chemical is indicated by its molar mass. It provides you with the amount of grams per mole of a substance, to put it another way.

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